Question

8.17 Lab: Strings of a Frequency Write a program that reads whitespace delimited strings (words) and an integer (freq). Then, the program outputs the strings from words that have a frequency equal to freq in a case insensitive manner.

Answer 1

Answer:

def occurencesOfWords(words,freq):

  frequency_dictionary={}

  matched_frequency_words=[]

  for i in range(len(words)):

      counter=1

      a=words[i].lower()

      for j in range(len(words)):

          if(i==j):

              continue

          b=words[j].lower()

          if(a==b):

              counter+=1

      frequency_dictionary[words[i]]=counter

  for key in frequency_dictionary:

      if(frequency_dictionary[key]==freq):

          matched_frequency_words.append(key)

  return matched_frequency_words

if __name__=='__main__':

  user_input=input()

  freq=int(input())

  words=user_input.split(" ");

  required_words=occurencesOfWords(words,freq)

  for s in required_words:

      print(s)

Explanation:

• Inside the occurencesOfWords function, initialize a frequency_dictionary that is used to store the string and the frequency of that specific string .
• matched_frequency_words is an array that is used to store each string whose frequency matches with the provided frequency
• Run a nested for loop up to the length of words and inside the nested for loop, skip the iteration if both variables i and j are equal as both strings are at same index.
• Increment the counter variable, if two string are equal.
• Loop through the frequency_dictionary to get the matching frequency strings .
• Finally test the program inside the main function.