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erma4kov [3.2K]
2 years ago
13

What explains the discrepancy between the number of bytes you can

Computers and Technology
1 answer:
sergejj [24]2 years ago
8 0

Answer:

This is because, the advertisers report the storage space in decimal while the computer reads the storage space in binary.

Explanation:

The advertisers report the storage space in decimal or base 10 because humans count in decimal, whereas the computer reports the storage space in binary or base 2.

Since the computer storage is in bytes and 8 bits equal 1 byte, It is easier to write a storage space of 1 kB as 1000 B but it is actually supposed to be 1024 B(2¹⁰). So, there is a discrepancy of 1024 B - 1000 B = 24 B.

As  we go higher, the discrepancy increases. For example, 1 MB is advertised as 1000 kB = 1000000 B but is actually supposed to be 1024 kB = 1024 × 1024 B = 1048576 B. So, there is a discrepancy of 1048576 B - 1000000 B = 48576 B.

So, the actual number of bytes on the storage device is actually less than that reported due to the different number systems in which they are reported in. This discrepancy is less in memory cards or flash drives though in which the stated value of storage capacity might be the actual storage size.

Note that the base 10 or decimal system was chosen by advertiser since this is what consumers understand.

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Answer:

I think the answer is Writing but am not sure

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2 years ago
C program how to input this? ​
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What is a form of technology that you think will make your life easier?
zzz [600]

Answer:

Digital communication technologies

Explanation:

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3 years ago
Write a program that prompts the user to input a number. The program should then output the number and a message saying whether
Gala2k [10]

Answer:

Following is the program in C++ Language

#include <iostream> // header file

using namespace std; // namespace std

int main() // main method

{

   int n;  // variable declaration

   cout<<" Please enter the number :";

   cin>>n; // Read the number

   if(n>0) // check the condition when number is positive

   {

cout<<n<<endl<<"The number is Positive"; // Display number

   }

  else if(n<0) // check the condition when number is Negative

  {

cout<<n<<endl<<"The number is Negative";// Display number

  }

  else // check the condition when number is Zero

  {

cout<<n<<endl<<"The number is Zero";// Display number

  }

   return 0;

  }

Output:

Please enter the number:

64

The number is Positive

Explanation:

Following are the description of the program

  • Declared a variable "n" of int type.
  • Read the value of "n" by user.
  • Check the condition of positive number by using if block statement .If n>0 it print the number is positive.
  • Check the condition of negative number by using else if block statement If n<0 it print the number is negative.
  • Finally if both the above condition is fail it print the message " The number is Zero"

7 0
3 years ago
Which of the following are true about the PUSH instruction?
kkurt [141]

Answer:

Option A.

Explanation:

Only option A satisfies the definition of push statements. So it is only the correct option.

7 0
3 years ago
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