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Nataliya [291]
4 years ago
7

+

Mathematics
2 answers:
Murljashka [212]4 years ago
4 0

Answer:

11

Step-by-step explanation:

The sum of the shortest two sides must be greater than the longest side.

If n is the longest side:

6 + 8 > n

14 > n

If 8 is the longest side:

6 + n > 8

n > 2

So n must be an integer greater than 2 and less than 14.

n can be 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, or 13.

There are 11 possible integers.

Lostsunrise [7]4 years ago
3 0

\LARGE{ \boxed{ \rm{ \purple{Answer}}}}

We know,

Sum of two sides of a triangle > Third side

Then,

⇛ 6 + 8 > n

⇛ 14 > n

Nextly,

Difference of two sides of a triangle < Third side

Then,

⇛ 8 - 6 < n

⇛ 2 < n

Then, Range of third side:

☃️ <u>2 < n < 14</u>

Possible measures of 3rd sides = 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 or 13.

There are 11 possible values of 3rd side. Out of them, any measure is the length of 3rd side.

<u>━━━━━━━━━━━━━━━━━━━━</u>

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Figure out this number pattern:<br>1,5,14,30,55
Amanda [17]

5 - 1 = 4 = 2^2

14 - 5 = 9 = 3^2

30 - 14 = 16 = 4^2

55 - 30 = 25 = 5^2

Start with 1, then add 2^2, 3^3, 4^2, 5^2, 6^2, etc.

5 0
4 years ago
The lower supports are and the area of the two supports is square meters. The upper arch can be decomposed as one semicircle wit
Galina-37 [17]

Answer:

 The lower supports are <u>Congruent Rectangles</u> and the area of the two supports is<u> 24 square meters.</u>

The upper arch can be decomposed as one semicircle with radius<u> 6 </u>meters minus a semicircle with radius 3 meters.

The area of the archway is <u>(13.5 π</u> + 24) square meters.

Step-by-step explanation:

See attachment for the firgure,

In order to determine the area of archway = The area of upper support + area of lower support.

As given, the lower support are two congruent rectangles consists of dimension 3 m × 4 m

Therefore, the area of lower support can be written as,

The area of lower support = 3 × 4 + 3 × 4 = 12 + 12 = 24 square m.

Now, the upper support arch can be decomposed as the two concentric semi circles having radius 3 m and 6 m,

Hence, the area of the upper support = Area of semi circle having radius i.e 6 m - Area of semi circle having radius i.e 3 m

=> π6²/2 - π3²/2= 27π/2= 13.5π square m

Therefore, the area of the archway =  (13.5 π + 24) square meters

4 0
4 years ago
What sides are the Adjacent, Hypotenuse, Opposite?
devlian [24]

9514 1404 393

Answer:

  • sin(Z) = 9/15 = 3/5
  • cos(Z) = 12/15 = 4/5

Step-by-step explanation:

The hypotenuse is the longest side, XZ (15). It is opposite the right angle (Y).

The segments adjacent to Z are the ones with Z in their name: ZX and ZY. When we talk about the "side" or "leg" adjacent to Z, we are usually not interested in the hypotenuse ZX. We refer to that as the "hypotenuse." So, the side or leg "adjacent" to Z is ZY, of length 12.

The segment opposite to Z is the one that does not have Z in its name: XY.

  sin(Z) = Opposite/Hypotenuse = XY/XZ = 9/15 = 3/5

  cos(Z) = Adjacent/Hypotenuse = YZ/XZ = 12/15 = 4/5

5 0
3 years ago
What is the solution to the equation 1/5n = 3 ?​
Cloud [144]

This is my answer :)))

5 0
3 years ago
Let P(x) = F(x)G(x) and Q(x) = F(x)/G(x), where F and G are the functions whose graphs are shown.
Leto [7]
Hello,

Very nice like question!

a)
F(2)=3 ; G(2)=2
F'(2)=0; G'(2)=1/2
P'(x)=F'(x)*G(x)+F(x)*G'(x)

P'(2)=0*2+3*1/2=3/2

b)
F(7)=5; G(7)=1
F'(7)=1/4; G'(7)=-2/3

Q'(x)=(F'(x)*G(x)-F(x)*G'(x)) / G²(x)

Q'(7)=(1/4*1-5*(-2/3))/1²=1/4+5/3=23/12




7 0
3 years ago
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