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marishachu [46]
2 years ago
8

Which is true:0/4 = 0or, 4/0 = 0​

Mathematics
2 answers:
inessss [21]2 years ago
6 0

Answer:

0 / 4 = 0, this is true

Step-by-step explanation:

4 / 0 is not defined.

Readme [11.4K]2 years ago
4 0
It's the first one 0/4 = 0
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What is the value of x?
Andreas93 [3]

Answer:

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Evaluate 15 - 151.<br> -10<br> 10<br> 20<br> -20
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Step-by-step explanation:

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Which of the following functions are solutions of the differential equation y'' + y = sin(x)? (Select all that apply.) y = − 1
Svetach [21]

The function that is the solution of the differential y" + y = sin(x) is: y(x) = -1/2(x cos x)

<h3>What is a function?</h3>

A function is an expression, rule, or law in mathematics that describes a connection between one factor (the independent variable) and another variable (the dependent variable).

<h3>What is the proof of the above function?</h3>

Take a look at the the following differential equation:

y" + y = sin (x)

The auxiiliary equation is

m² + 1 = 0

m² + 1-1 = -1

m² + 0 = -1

m² = -1

m = ±√-1

m = ±i

So, the complimentary function is yₐ (x) = c₁ cos x + c₂ sin x

Let the particular integral be:

yₙ (x) = A cos x + B sin x

yₙ '(x) = - A sin x + B cos x

yₙ ''(x) = - A cos x + B cos x

yₙ ''(x) = - (A cos x + B cos x)

After we have substituted yₙ (x); and yₙ''(x) in the given differential equation

y'' + y = sin (x)

= - (A cos x + B cos x) + (A cos x + B cos x)  = sin(x)

0 = sin (x)

If we take the particular integral to be:
yₙ (x) =  x(A cos x + B cos x)

yₙ '(x) = x(-A sin x + B cos x) + A cos x + B cos x

yₙ ''(x) = x(-A cos x - B sin x) - A sin x + B cos x + -A sin x + B cos x

Substitute yₙ (x), yₙ''(x) into the stated differential equation

y'' + y = sin (x)

x (-Acosx - Bsin x) - Asinx + Bcosx + (-Asinx + Bcosx) - x (Acosx + Bsin x) = sin (x)

-Axcosx - Bxsin x - Asinx + Bcosx -Asinx + Bcosx - Axcosx + Bxsin x = sin (x)

-2Asinx + 2Bcosx = sin(x)

Compare the coefficients of like terms on both sides of the equation

-2A = 1, B = 0

A = -1/2, B = 0

Substitute A = -1/2, B =0 into the assumed solution.

yₙ(x) = x((-1/2)cosx + (0) sinx)

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Now, the general solution for the given differential equation is:

y(x) = yₓ(x) +yₙ (x)

y (x) - c₁cosx + c₂sin x -1/2x cosx

Hence, the solution is:

y(x) = -1/2xcosx

Learn more about function at;
brainly.com/question/25638609
#SPJ1

Full Question:

Which of the following functions are solutions of the differential equation y'' + y = sin x? (Select all that apply.)

A) y = 1 2 x sin x

B) y = cos x

C) y = x sin x − 5x cos x

D) y = − 1 /2 x cos x

E) y = sin x

4 0
2 years ago
The solution to 9(x + 2) = 5 - 2(x - 1) is<br> 1. -4<br> 2. -1<br> 3. - 5/6<br> 4. 5/6
7nadin3 [17]

Answer:

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Step-by-step explanation:

I am not certain but here

so you first distribute x and 2 with 9 to get 9x+18

then you do the same thing to the other side so you have -2x-2

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Next you will add 5 to 2 making it 7

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now add 2x to both sides

then you should end up will 11x=-11

simplify and you get -1

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Weekly:1,173

Daily: 235

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