<span>NCn is always equal to 1. </span>
About 3,000 pounds of confetti is dropped.
Answer:
v = 7
is the value for which
x = (-21 - √301)/10
is a solution to the quadratic equation
5x² + 21x + v = 0
Step-by-step explanation:
Given that
x = (-21 - √301)/10 .....................(1)
is a root of the quadratic equation
5x² + 21x + v = 0 ........................(2)
We want to find the value of v foe which the equation is true.
Consider the quadratic formula
x = [-b ± √(b² - 4av)]/2a ..................(3)
Comparing (3) with (2), notice that
b = 21
2a = 10
=> a = 10/2 = 5
and
b² - 4av = 301
=> 21² - 4(5)v = 301
-20v = 301 - 441
-20v = -140
v = -140/(-20)
v = 7
That is a = 5, b = 21, and v = 7
The equation is then
5x² + 21x + 7 = 0
First add 2y to both sides
so 4 + 3x + 2y = 0
then subtract 4 from both sides
so 3x + 2y = -4
that is standard form
now subtract 3x from both sides
2y = 3x - 4
now divide by 2 on both sides
y = 1.5x - 2
This is solved for y and is slope intercept form
starting from original subtract 4 from both sides
so 3x = -2x -4
now divide by 3 on both sides
so x = -2/3x -4/3
this is solved for x
hope any of that is what you needed.
The answer is C. If you use the pythagorean theorem,
, and connect the two points together at a right angle and pug in the lengths of the two lines to the equation then the answer should be C.
