Question

Solve by factoring... 1) y=6x^2-13x-5 2) y=4x^2-7x+3

Answer 1

Answer:

1) $x=-\frac{1}{3}, x=\frac{5}{2}$

2) $x=1, x=\frac{3}{4}$

Step-by-step explanation:

1)

Given

$f(y)= 6x^{2} -13x-5=0$

Equating above equation.

$6x^{2} +2x-15-5=0$

$2x(3x+1)-5(3x+1)=0$

$(3x+1)(2x-5)=0$

Solving for both the equation

$3x+1=0$

$3x=-1$

$x=-\frac{1}{3}$

$2x-5=0$

$2x=5$

$x=\frac{5}{2}$

$x=-\frac{1}{3} ,x=\frac{5}{2}$

2)

Given

$f(y)=4x^{2} -7x+3=0$

$4x^{2} -4x-3x+3=0$

$4x(x-1)-3(x-1)=0$

$(x-1)(4x-3)=0$

Solving for both equation

$x-1=0$

$x=1$

$4x-3=0$

$4x=3$

$x=\frac{3}{4}$

$x=1, x=\frac{3}{4}$