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Juli2301 [7.4K]
4 years ago
10

Solve by factoring... 1) y=6x^2-13x-5 2) y=4x^2-7x+3

Mathematics
1 answer:
Amanda [17]4 years ago
8 0

Answer:

1) x=-\frac{1}{3}, x=\frac{5}{2}

2) x=1, x=\frac{3}{4}

Step-by-step explanation:

1)

Given

f(y)= 6x^{2} -13x-5=0

Equating above equation.

6x^{2} +2x-15-5=0

2x(3x+1)-5(3x+1)=0

(3x+1)(2x-5)=0

Solving for both the equation

3x+1=0

3x=-1

x=-\frac{1}{3}

2x-5=0

2x=5

x=\frac{5}{2}

x=-\frac{1}{3} ,x=\frac{5}{2}

2)

Given

f(y)=4x^{2} -7x+3=0

4x^{2} -4x-3x+3=0

4x(x-1)-3(x-1)=0

(x-1)(4x-3)=0

Solving for both equation

x-1=0

x=1

4x-3=0

4x=3

x=\frac{3}{4}

x=1, x=\frac{3}{4}

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You invested money in a fund and each month you receive a payment for your investment. Over the first four months, you received
Alexus [3.1K]

Money received in tenth month: $104

Difference between explicit formula and a recursive formula is: the use of (n-1)th term, nth term and the common difference (d) brings a great difference between the two formulae of an arithmetic progression.

<h3>What is arithmetic progression?</h3>

A series of numbers called an arithmetic progression or arithmetic sequence (AP) has a constant difference between the terms.

Given:

  • Money received in first four months: $50, $52, $55, %59.

To find: Money received in tenth month.

Finding:

As we can see, the pattern followed here is: increment in each amount received each month by $1. Thus it is an arithmetic progression.

That is: 50, 52 (0+2), 55 (2+3), 59 (2 + 3 + 4) and so on.

Thus, for the tenth month, we can use the formula of recursion, given by: a_n=a_{n-1}+n, n ≥ 1.

For a₁ = 50, a₂ = a₁ + 2

=> a₂ = 50 + 2

This way, a₅ = a₄ + 5

=> a₅ = 59 + 5 = 64

a₆ = a₅ + 6

=> a₆ = 64 + 6 = 70

a₇ = a₆ + 7

=> a₇ = 70 + 7 = 77

a₈ = a₇ + 8

=> a₈ = 77 + 8 = 85

a₉ = a₈ + 9

=> a₉ = 85 + 9 = 94

a₁₀ = a₉ + 10

=> a₁₀ = 94 + 10 = 104

Thus, the payment received in tenth month will be $104.

(b) Difference between explicit formula and recursive formula of an arithmetic progression:

  • The first term of a recursive formula is a₁ and the formula for the nth term uses the first term and the common difference, d. One example of a recursive formula is a_n=a_{n-1}+d.
  • A formula for the nth term in an explicit formula would include the initial term a₁, the common difference d, and the term number, n. The equation a_n = a_1 + (n-1)d.

To learn more about arithmetic Progressions, refer to the link: brainly.com/question/6561461

#SPJ4

6 0
1 year ago
3a-2/3+2a+3/2=a+7/6.find a ​
S_A_V [24]

I think your question seems to be ;

{\:\implies \quad \sf 3a-\dfrac23 +2a+\dfrac32 =a+\dfrac76}

So I will be solving for that ;

{\:\implies \quad \sf 3a+2a+\left(\dfrac32 -\dfrac23\right)=a+\dfrac76}

{\:\implies \quad \sf 5a+\left(\dfrac{9-4}{6}\right)=a+\dfrac76}

{\:\implies \quad \sf 5a+\dfrac56 =a+\dfrac76}

{\:\implies \quad \sf 5a-a=\dfrac76 -\dfrac56}

{\:\implies \quad \sf 4a=\dfrac{7-5}{6}}

{\:\implies \quad \sf 4a=\dfrac26}

{\:\implies \quad \sf 4a=\dfrac13}

{\:\implies \quad \sf a=\dfrac{1}{3\cdot 4}}

{\:\implies \quad \bf \therefore \quad \underline{\underline{a=\dfrac{1}{12}}}}

7 0
3 years ago
PLEASE HELP! WILL GIVE YOU BRAINLEST
mixas84 [53]

Answer: b

the answer is b

in order to solve for AB you need to use the pythagorean theorem by making a triangle with AB as one of the sides of the triangle.

plot each point A and B and connect it and connect point B with the x-axis, (3,0) You'll see athat a triangle has formed. All you have to do after that is apply the Pythagorean theorem.

the distance from A to the new point (3,0) is 3, the distance from the new point to B is 4. Line AB will be the hypotenuse.

Pythagorean therom is a^2+b^2=c^2

so 3^2+4^2=c^2

  = 9+16=25

square root the 25 and you get a 5.

5 0
3 years ago
Jack can build 1/5 of a shed in the same time Kyle build 5/8 of a shed. How much of a shed will jack have built when Kyle has fi
nadya68 [22]

Answer:

Step-by-step explanation:

If Kyle can get 5/8 of a shed built in x amount of time, he can get 62.5% done; if Jack can get 1/5 of the shed built in the same time, he can 20% of it done. As a ratio:

\frac{Kyle}{Jack}:\frac{62.5}{20}  Kyle gets the whole thing done, 100% of the way, leaving Jack lagging behind at a somewhat lower percentage of the work being done.

\frac{Kyle}{Jack}:\frac{62.5}{20}=\frac{100}{x} and cross multiply to solve for the percentage of the shed built by Jack by the time Kyle gets it completed:

62.5x = 2000 so

x = 32%

4 0
3 years ago
Need help with this problem immediately
NISA [10]

=168.96m

that's my answer

hope it's help

7 0
3 years ago
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