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4 years ago

Write an equation for the line parallel to y= -7x+15 that contains p(9,-6)

1 answer:

5 0

The slope of the line we seek must me the same as the slope of the given line because THE LINES ARE PARALLEL.

The two lines never meet.

The slope of the given line is -7.

See it?

Plug -7 and the given point into the point-slope formula.

y - (-6) = -7(x - 9)

Solve for y.

y + 6 = -7x + 63

y = -7x + 63 - 6

y = -7x + 57

Did you follow?

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JulijaS [17]

Answer:

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3 years ago

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Yakvenalex [24]

Answer:

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Step-by-step explanation:

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2 years ago

Cuál es la probabilidad teórica de obtener un 2 o un 3 al tirar un cubo numérico?

VARVARA [1.3K]

Answer:

c)1/3

Step-by-step explanation:

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4 0

4 years ago

Please help, basic algebra. Find the value of x

Helga [31]

Answer: x = 131

Reasoning: Alternate interior angle theorem

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7 0

3 years ago

The original line has the equation of y=-2x+8

enot [183]

The new equation of line that is perpendicular to the original that goes through the point (6, -1) in slope intercept form is $y = \frac{1}{2}x - 4$

<h3>Solution:</h3>

Given that original line has the equation of y = -2x + 8

We have to write a new equation that is perpendicular to the original that goes through the point (6, -1)

Let us first find slope of original line

The slope intercept form of line is given as:

y = mx + c ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

On comparing the slope intercept form and given original equation, we get "m = -2"

Thus slope of original line "m" = -2

We know that product of slope of a line and slope of line perpendicular to it are always -1

slope of original line x slope of line perpendicular to it = -1

$\begin{array}{l}{-2 \times \text { slope of line perpendicular to it }=-1} \\\\ {\text { slope of line perpendicular to it }=\frac{1}{2}}\end{array}$

Let us find equation of line with slope m = 1/2 and passes through point (6, - 1)

Substitute $m = \frac{1}{2}$ and (x, y) = (6, -1) in eqn 1

$-1 = \frac{1}{2} \times 6 + c\\\\-1 = 3 + c\\\\c = -4$

Thus the required equation of line is:

Substitute "c" = -4 and $m = \frac{1}{2}$ in eqn 1

$y = \frac{1}{2}x - 4$

Thus the equation of line perpendicular to original line is found

7 0

3 years ago