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Tomtit [17]
3 years ago
7

Car park algebra question

Mathematics
1 answer:
Svetllana [295]3 years ago
5 0
You did south, north, correctly

but last one

twice north is 2 times (x+48) or 2x+96


so

s=x
n=x+48
c=4x
s+c>2x+96
subsitute s for x and 4x for c
x+4x>2x+96
5x>2x+96
minus 2x both sides
3x>96
divide both sides by 3
x>32
it cannot be equal to 32 so
the minimum value is 33 spaces in south car park
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In your denominator, you have (x+7)(x-5)(x-3).
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If x = -7, if x = 5, or if x = 3, then that entire expression will equal zero. (Same idea as when you solve equations by factoring.

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3 years ago
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AveGali [126]

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