$(5^1^8 - 25^8) (16^4-2^1^3-4^5)\\=(5^1^8 - 5^2^\times^8) (2^4^\times^4 - 2^1^3 - 2^2^\times^5)\\=(5^1^8 - 5^1^6)(2^1^6-2^1^3-2^1^0)\\=(5^2) ( 2^3-2^1^0)\\=(25) (8-1024)\\=(25) \times (-1016)\\= -25400$

To check the number -25400 be divisible by 30 and 44, divide the number -25400 by 30 and 44

On dividing -25400 by 30 we get, -846.66

On dividing -25400 by 44 we get, -577.27

Therefore,

The value of the expression is not divisible by 30 and 44.

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4 years ago

Will name Branliest! Solve for x. x/3≤−6

kobusy [5.1K]

Answer:

x ≤ -18. I hope this helps

Step-by-step explanation:

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840, 180, 40, 10,...

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Exponential decay and range will be the set of natural numbers

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