The solution for the inequalities 3y>2x+12, 2x+y<=-5 is the value of x<-27/8 and y<7/4.
Given 3y>2x+12 and 2x+y<=-5.
We are given two inequalities 3y>2x+12 and 2x+y<=-5. Inequality are like equations but in greater than ,less than or in combination with equal to. To solve them we need to first write them properly.
2x-3y<-12
2x+y<=-5
Now assume these are equalities
2x-3y=-12
2x+y=-5
now subtract 2 from 1
2x-3y-2x-y=-12+5
-4y=-7
y=7/4
put the value of y in 2x-3y=-12
2x-3(7/4)=-12
2x-21/4=-12
2x=-12+21/4
2x=(-48+21)/4
2x=-27/4
x=-27/8
Now put the signs between the values
x<-27/8
y<7/4.
Hence the solution of the inequalities 3y > 2x + 12
2x + y ≤ -5 is the value of x<-27/8 and y<7/4.
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Answer:
$367.17
Step-by-step explanation:
we are find the cost of the car after 5 years
Using the compound interest formula;
A = P(1+r/n)^nt
Given
Principal P = $300
rate r = 5.2% = 0.052
Time t = 5years
Time of compounding n = 1/12 (monthly)
Substitute into the formula
A = 300(1+0.052(12))^5(1/12)
A = 300(1+0.624)^0.4167
A = 300(1.624)^0.4167
A = 300(1.2239)
A = 367.17
hence the amount of the car after 5years is $367.17
Answer:
all of them but dilation..y+6.. (x,y)>(x,-y) enlargement.. reduction..sorry I dont know the 4th one the 6th one and the last one
Hi there
First find the labor cost
$8/h * 80h = $640
labor cost as a percentage of revenue
$640 / $2000 = .32×100=32%
Hope it helps