3 divided by 1/8 = <em>24 and 0/8</em>
B = g + 12
g + b = 124
Replace the b in the second equation with
g+ 12
g+ g+12=124
2g + 12 = 124
Subtract 12 from both sides
2g = 112
Divide by 2
g = 56
b= 56 + 12
b= 68
So in order to find line AC you must find line AD and DC then plus them together.
to find AD use Pythagoras theorem
a^2 = c^2 - b^2
AD^2 = 7.5^2 - 6.5^2
AD^2 = 56.25 - 42.25
AD^2 = 14
square root both sides to get rid of the ^2
AD ≈ 3.7 or 3.74
Do the same for DC
DC^2 = 10^2 - 6.5^2
DC^2 = 100 - 42.25
DC^2 = 57.75
DC ≈ 7.6
now plus AD and DC which should give u 11.3
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