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3 years ago

PLEASEE HELPP MEEEEE !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

Ksju [112]3 years ago

7 0

G(x)= $x^{2}$ +2

maxonik [38]3 years ago

6 0

The answer is A. Let me know if you need anything else

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A test consists of 10 true or false questions. To pass the test a student must answer at least eight questions correctly. If the

forsale [732]

<h3>The probability of student passing the quiz with at least 50% of the questions correct is 0.05457.</h3>

Step-by-step explanation:

Here, the total number of T/F question = 10

The minimum answers needed correctly answered = 8

So, student needs to answer at least 8 questions correctly.

Here, the possibility of answering a question correctly = $(\frac{1}{2})$ = p = 0.5

Also, the possibility of answering a question wrong = $(\frac{1}{2})$ = q = 0.5

Now, to pass he needs to answer 8 or more ( 8 , 9 or 10) answers correctly.

P(answering 8 correct answer) = $^{10}C_8(p)^8(q)^2 = ^{10}C_8(0.5)^8(0.5)^2 = 0.0439$

P(answering 9 correct answer) = $^{10}C_9(p)^9(q)^1 = ^{10}C_9(0.5)^9(0.5)^1 = 0.0097$

P(answering 10 correct answer) = $^{10}C_{10}(p)^{10}(q)^0 = ^{10}C_{10}(0.5)^{10}(0.5)^0 = 0.00097$

So, the total Probability = P(8) + P(9) + P(10)

= (0.0439) + (0.0097) + (0.00097)

= 0.05457

Hence, the probability that the student passes the quiz with at least 8 of the questions correct is 0.05457.

6 0

3 years ago

What is the solution to the equation below?Round your answer to two decimal places.3*In x=9.9

storchak [24]

See photo for solution

8 0

3 years ago

Show work and Factor 4x^2+xy-18y^2

grigory [225]

Answer:

$4x^2+xy-18y^2=(4x+9y)\,(x-2y)$

Step-by-step explanation:

Let's examine the following general product of two binomials with variables x and y in different terms:

$(ax+by)\,(cx+dy)= ac\,x^2+adxy+bcxy+bdy^2$

so we want the following to happen:

$a\,c = 4\\ad+bc=1\\bd--18$

Notice as well that $ad+bc =1$ means that those two products must differ in just one unit so, one of them has to be negative, or three of them negative. Given that the product $bd=-18$ , then we can consider the case in which one of this (b or d) is the negative factor. So let's then assume that $a\,\,and \,\,c$ are positive.

We can then try combinations for $a\,\,and \,\,c$ such as:

$a = 4;\,\,c=1\\a=2;\,\,c=2\\a=1;\,\,c=4$

Just by selecting the first one $(a=4;\,\,c=1)$

we get that $4d_b=1\\b=-4d-1$

and since

$bd=-18\\(-4d-1)\,d=-18\\-4d^2-d=-18\\4d^2+d-18=0$

This quadratic equation give as one of its solutions the integer: d = -2, and consequently,

$d=-18/(-2)\\d=9$

Now we have a good combination of parameters to render the factoring form of the original trinomial:

$a=4; \,\,b=9;\,\,c=1;\,\,d=-2$

which makes our factorization:

$(4x+9y)\,(x-2y)=4x^2+xy-18y^2$

6 0

3 years ago

I just need to know the answer to B.

sleet_krkn [62]

Answer:

24%

Step-by-step explanation:

45 + 37 + 52 + 94 + 72 = 300

72/300 = 0.24 x 100

= 24%

7 0

3 years ago

How to solve x=6y-11 and 3x-2y=-1 by substitution

vagabundo [1.1K]

Substitute x into the second equation:
3(6y-11)-2y=-1
18y-33-2y=-1
16y=32
y=2
Then put the y value into the first equation to get x:
x=6(2)-11
x=1
There you go!

Please mark brainliest

7 0

3 years ago