Identify the oblique asymptote of f(x)=x+4/3x^2+5x-2
1 answer:
Answer:
No oblique asymptote
Step-by-step explanation:
To find the oblique asymptote of f(x)
Here numerator has degree 1 and denomintor degree 2
Degree of numerator < Degree of denominator
Hence there is no oblique asymptote
When the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly, giving us a horizontal asymptote of the x-axis. Or we can write
f(x) = a polynomial of x + a proper fraction.
In this case only we have oblique asymptotes but not when numerator has less degree.
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Given the function:
Let's find the amplitude and period of the function.
Apply the general cosine function:
Where A is the amplitude.
Comparing both functions, we have:
A = 1
b = 4
Hence, we have:
Amplitude, A = 1
To find the period, we have:
Therefore, the period is = π/2
The graph of the function is shown below:
The parent function of the given function is:
Let's describe the transformation..
Apply the transformation rules for function.
We have:
The transformation that occured from f(x) = cosx to g(x) = cos4x using the rules of transformation can be said to be a horizontal compression.
ANSWER:
Amplitude = 1
Period = π/2
Transformation = horizontal compression.
