The answer is A, 651. You would first start by multiplying the number of students, 1,860, by 45%, or .45. You'd come out with the answer of 837. You would then add 837 and 372 together to get a sum of 1,209. Finally, you would subtract 1,209 from the total number of students, which was 1,860 and get an answer of 651. I hope this helped you understand how a problem like this should be worked out!
Answer:
(4x+5)/[(x-1)(x-2)]
Step-by-step explanation:
(4x+5)/(x^2-3x+2)
factor out the trinomial x^2-3x+2 first,
find two numbers that when they multiply, you get the third term, which is 2 in this case. And when they add up, you get the second term, which is -3 in this case. x^2-3x+2=(x-1)(x-2)
Answer:
a:c = 35:24
a:c = 20:27
a:c = 35:22
a:c = 28:27
Step-by-step explanation:
a:b = 7:3
Using cross products
3a = 7b
Divide by 7
3a/7 = b
Now we want
8b = 5c
Substitute in 3a/7 for b
8 (3a/7) = 5c
24/7a = 5c
Multiply by 7
24/7a *7 = 5*7c
24a = 35c
Divide by c
24 a/c = 35
Divide by 24
a/c = 35/24
a:c = 35:24
a:b = 4:9
Using cross products
9a = 4b
Divide by 4
9a/4 = b
Now we want
3b = 5c
Substitute in 9a/4 for b
3 (9a/4) = 5c
27/4a = 5c
Multiply by 4
27/4a *4 = 5*4c
27a = 20c
Divide by c
27 a/c = 20
Divide by 27
a/c = 20/27
a:c = 20:27
b:c = 5:11
Using cross products
11b = 5c
Divide by 11
b = 5c/11
Now we want
2a = 7b
Substitute in 5c/11 for b
2a = 7(5c/11)
2a = 35c/11
Multiply by 11
2a*11 = 35c
22a = 35c
Divide by c
22 a/c = 35
Divide by 22
a/c = 35/22
a:c = 35:22
b:c = 14:3
Using cross products
3b = 14c
Divide by 3
b = 14c/3
Now we want
9a = 2b
Substitute in 14c/3 for b
9a = 2(14c/3)
9a = 28c/3
Multiply by 3
9a*3 = 28c
27a = 28c
Divide by c
27 a/c = 28
Divide by 27
a/c = 28/27
a:c = 28:27
Answer:
Equation ; y = 6x +29
Step-by-step explanation:
slope(m)= 6
passing through (-6,7) = (x₁ ,y₁)
Now,
y-y₁ = m (x - x₁)
y-7 = 6(x- (-6) )
y-7 = 6x +36
y= 6x +29
which is the required eqn