A) The situation represents an arithmetic sequence because the successive y-values have a common difference of 210.
F(1) = 240 +210
F(2) = 240 +2(210)
F(3) = 240+3(210)
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F(x)= 240 +210x.
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A quotient of a number 21 is 3 and 63
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Answer:
Step-by-step explanation:
![\sf h(x) = 5x+2\\\\Put \ h(x) = -8\\\\-8 = 5x+2\\\\Subtract \ 2 \ to \ both \ sides\\\\-8-2 = 5x\\\\-10 = 5x\\\\Divide\ both \ sides \ by \ 5\\\\-10 / 5 = x \\\\x = -2 \\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%20h%28x%29%20%3D%205x%2B2%5C%5C%5C%5CPut%20%5C%20h%28x%29%20%3D%20-8%5C%5C%5C%5C-8%20%3D%205x%2B2%5C%5C%5C%5CSubtract%20%5C%202%20%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5C-8-2%20%3D%205x%5C%5C%5C%5C-10%20%3D%205x%5C%5C%5C%5CDivide%5C%20both%20%5C%20sides%20%5C%20by%20%5C%205%5C%5C%5C%5C-10%20%2F%205%20%3D%20x%20%5C%5C%5C%5Cx%20%3D%20-2%20%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
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<h3>~AH1807</h3>
Answer:
Theo worked for 12 hours and Kade worked for 15
Step-by-step explanation:
if kade worked for 10 hours Theo works for 7 so in total they worked for 17 hours together. So what you do is you just continue counting kades hours, subtracting 3 then add those number together till you get the total of 27 hours.
