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Gnoma [55]
3 years ago
5

∠R and ∠S are complementary. If m∠R = (2x+7) and m∠S = (4x - 13), find m∠R

Mathematics
2 answers:
BlackZzzverrR [31]3 years ago
4 0

Answer:

39°

Step-by-step explanation:

Complementary angles add up to 90

2x + 7 + 4x - 13 = 90

6x - 6 = 90

6x = 96

x = 16

Angle R = 2(16) + 7

32 + 7

39°

____ [38]3 years ago
3 0

Answer:

m∠R = 39 degrees

Step-by-step explanation:

As complementary angles add up to 90 degrees, we can set up an equation to get x then find the measure of ∠R:

m∠R + m∠S = 90

2x+7+4x-13=90

6x+7-13=90

6x-6=90

6x=96

x=16

Since m∠R = (2x+7), 2x+7 would be 2(16)+7 or 39 degrees. So in conclusion, m∠R = 39 degrees

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5 0
2 years ago
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prohojiy [21]

Answers:

  • slower train = 139 km per hour
  • faster train = 159 km per hour

=================================================

Explanation:

x = rate of the slower train

x+20 = rate of the faster train

rates are in km per hour, abbreviated as kph

The train traveling at x kph will travel 5x km after 5 hours.

Use this formula

distance = rate*time

Using that same formula, the faster train travels 5(x+20) = 5x+100 kilometers in 5 hours.

The two distances must add to 1490 if we want the trains to pass by each other. Assume that the trains are traveling on parallel side-by-side tracks.

--------------------------

So,

(slower train distance) + (faster train distance) = 1490

(5x) + (5x+100) = 1490

10x+100 = 1490

10x = 1490-100

10x = 1390

x = 1390/10

x = 139

The slower train moves at a rate of 139 km per hour.

x+20 = 139+20 = 159

The faster train moves at a speed of 159 km per hour.

--------------------------

Check:

The slower train travels 139 kph and travels for 5 hours, so it covers a distance of 139*5 = 695 km

The faster train has a speed of 159 kph and travels for 5 hours, so it covers 159*5 = 795 km

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The answers are confirmed.

7 0
2 years ago
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