5 times a number decreased by thirteen. Not sure if there should be the =12, so I didn't include it in the verbal description. Hope it helps!
Answer: 0.86 of the exam scores are between 68 and 77.99 points
Step-by-step explanation:
Since the set of computer science exam scores are normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = computer science exam scores .
µ = mean score
σ = standard deviation
From the information given,
µ = 71.33 points
σ = 3 points
We want to find the proportion of the exam scores are between 68 and 77.99 points. It is expressed as
P(68 ≤ x ≤ 77.99)
For x = 68,
z = (68 - 71.33)/3 = - 1.11
Looking at the normal distribution table, the probability corresponding to the z score is 0.13
For x = 68,
z = (77.99 - 71.33)/3 = 2.22
Looking at the normal distribution table, the probability corresponding to the z score is 0.99
P(68 ≤ x ≤ 77.99) = 0.99 - 0.13 = 0.86
1 yr = 12 months
- 2931/12 = - 244.25 per month
Answer:
(26.2252 ; 27.3748)
Step-by-step explanation:
The confidence interval is given by :
x ± Margin of error
The margin of error = Zcritical * (σ/√(n))
σ = 7.5 ; n = 654
Zcritical = Zα/2 = 1.96
The margin of error = 1.96 * (7.5/√654) = 0.5748
The confidence interval :
Upper boundary = 26.8 + 0.5748 = 27.3748
Lower boundary = 26.8 - 0.5748 = 26.2252
(26.2252 ; 27.3748)
We are 95% confident that the mean BMI of the entire population will fall in between (26.2252 ; 27.3748)
Answer: 6
Step-by-step explanation:
For every 6 bagels, two are blueberry.
