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Anna007 [38]
2 years ago
12

Jesper can run 6 miles in 45 minutes. He is thinking about running in two different races, a 9-mile race and a 15-mile race. At

his current rate, how many more minutes will it take Jesper to complete the 15-mile race than the 9-mile race?
Mathematics
1 answer:
marin [14]2 years ago
4 0

Find minutes per mile by dividing time by distance:

45 minutes / 6 miles = 7.5 minutes per mile

Now multiply his speed by each distance:

7.5 x 9 = 67.5 minutes

7.5 x 15 = 112.5 minutes

Now subtract the two:

112.5 - 67.5 = 45 minutes more

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There were 8 pizzas at the pizza party for two families. The Houston family ate 2 2/3 pizzas.
ollegr [7]

Answer:2 pizzas

Step-by-step explanation:

2 2/3 and 2 5/6 can both be rounded to 3. Double that and you get 6. Since there were 8 pizzas originally,subtract 6 from 8 to get 2 remaining pizzas.

6 0
3 years ago
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Suppose that the sample standard deviation was s = 5.1. Compute a 98% confidence interval for μ, the mean time spent volunteerin
NISA [10]

Answer:

The 95% confidence interval would be given by (5.139;5.861)  

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

2) Confidence interval

Assuming that \bar X =5.5 and the ranfom sample n=1086.

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=1086-1=1085

Since the Confidence is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,1085)".And we see that t_{\alpha/2}=2.33

Now we have everything in order to replace into formula (1):

5.5-2.33\frac{5.1}{\sqrt{1086}}=5.139    

5.5+2.333\frac{5.1}{\sqrt{1086}}=5.861

So on this case the 95% confidence interval would be given by (5.139;5.861)    We are 98% confident that the mean time spent volunteering for the population of parents of school-aged children is between these two values.

5 0
3 years ago
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ludmilkaskok [199]

Answer: 1, 2, and 4

Step-by-step explanation:

3 0
3 years ago
Please help me somebody!!! I really struggle with this in math class!
Tresset [83]

Answer:

y - 9 = -\frac{4}{3}(x - 3)  

Step-by-step explanation:

Given the points (3, 9) and (9, 1), we must first solve for the slope of the line before proceeding with writing the point-slope form.

In order to solve for the slope (<em>m </em>), use the following formula:

m = (y₂ - y₁)/(x₂ - x₁)

Let (x₁, y₁) =  (3, 9)

     (x₂, y₂) = (9, 1)

Substitute these values into the given formula:

m = (y₂ - y₁)/(x₂ - x₁)

m = (1 - 9)/(9 - 3)

m = \frac{-8}{6} = \frac{-4}{3}

Therefore, the slope of the line, m = -4/3.

Next, using the slope, m = -4/3, and one of the given points, (x₁, y₁) = (3, 9), substitute these values into the following point-slope form:

y - y₁ = m(x - x₁)

y - 9 = -\frac{4}{3}(x - 3)  ⇒ This is the <u>point-slope form</u>.

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G it’s 6 answer hope it helps sorry if I wrong
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