Answer:
perpendicular
Step-by-step explanation:
When 2 lines intersect at any point, not just in the middle of each (that has nothing to do with it), and they meet to form right angles, the lines are perpendicular to one another and their slopes are opposite reciprocals.
To write the equation of a line, we use the equation: y = mx +b.
m is the slope of the line, which can be calculated using the equation:
m = (y2 - y1)/(x2 - x1)
We can choose any two points on the line to put into this equation. The red dots are at (0,0) and (-6,-2), so we will use those, but you would get the same answer by using any other pair of coordinates on the blue line.
m = (-2 - 0)/(-6 - 0) = 2/6 = 1/3
b is the y-intercept of the line. The y-intercept is the y-coordinate when the line crosses the y-axis. It crosses the y-axis at (0,0), so the y-intercept is 0.
Now, we plug our values back into the full equation to get the equation of the line.
y = mx + b
y = (1/3)x + 0
So the final answer is y = (1/3)x or y = x/3, depending on how you want to write it.
Answer:
B because 8 seeds from pack 1. u do 8 times 3 other packs which is 24 So in between 20-30 seeds will sprout
Answer:
The answer to your question is the third choice
Step-by-step explanation:
To solve this problem, just multiply 6 by each of the numbers of the matrix and simplify.
6 | 4 -2 1 | = | (6 x 4) (6 x -2) (6 x 1) |
| 7 3 0| | (6 x 7) (6 x 3) (6 x 0) |
= | 24 -12 6 |
| 42 18 0 |
The first choice is wrong because only multiply by six the first row.
The second and fourth rows are incomplete.
Lagrange multipliers:
(if
)
(if
)
(if
)
In the first octant, we assume
, so we can ignore the caveats above. Now,
so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of
.
We also need to check the boundary of the region, i.e. the intersection of
with the three coordinate axes. But in each case, we would end up setting at least one of the variables to 0, which would force
, so the point we found is the only extremum.
