3 years ago

What is the area of a regular hexagon with a side length of 5in and an apothem of 4.33in?

Mathematics

1 answer:

BartSMP [9]3 years ago

4 0

Answer:

64.95

Hope this helps :-)

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2. Solve for y. A 10.5 B 9 C 13.5 D 12

Vera_Pavlovna [14]

It’s A
Because if you subtract 12 from 96 you’ll get 8y=84 then divide both sides by 8 you get 21/2 simplify and get 10.5 or 10 1/2

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2 years ago

Dale tried to estimate the area of his backyard garden. He guessed it was 12 square meters. When he measured the dimensions late

Elena-2011 [213]

Answer:

cool

Step-by-step explanation:

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2 years ago

Solve 3/5=8/y. Round to the nearest tenth. 15.2 9.8 13.3 18.8

Sidana [21]

3/5 = 3/y
40 = 3y
Divide both by 3
Answer= 13.3

4 0

3 years ago

Dylan made $45,765 and Orlando made $34,715. Both boys worked for 6 months. How much more money did Dylan earn than Orlando per

Ymorist [56]

Answer:

$425

Step-by-step explanation:

45,765 divided by 26 equals 1,760.192307692308

34,715 divided by 26 equals 1,335.192307692308

1,760.192307692308-1,335.192307692308=425

5 0

2 years ago

Given that cos (x) = 1/3, find sin (90 - x)

ddd [48]

Answer:

$\sin(90^{\circ} - x)=\frac{1}{3}$

Step-by-step explanation:

Given: $\cos (x)=\frac{1}{3}$

We have to find the value of $\sin(90^{\circ} - x)$

Since Given $\cos (x)=\frac{1}{3}$

Using trigonometric identity,

$\sin(90^{\circ} - \theta)=\cos\theta$

Thus, for $\sin(90^{\circ} - x)$ comparing , we have,

$\theta=x$

We get,

$\sin(90^{\circ} - x)=\cos x=\frac{1}{3}$

Thus, $\sin(90^{\circ} - x)=\frac{1}{3}$

3 0

3 years ago

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