Percent increase from 2000 to 2001 is 12% and from 2001 to 2002 is 12.6%. Thus period of 2001 to 2002 has higher increase percentage.
<u>Solution:</u>
Given that,
Total circulation of local newspaper in 2000 = 3250
Total circulation of local newspaper in 2001 = 3640
Total circulation of local newspaper in 2002 = 4100
<em><u>Finding percent of increase in the newspaper’s circulation from 2000 to 2001:</u></em>
<em><u>Finding percent of increase in the newspaper’s circulation from 2001 to 2002:</u></em>
As we can see 12% < 12.6%
So period of 2001 to 2002 has higher increase percentage.
Answer:
1 mi/1.61 km
Step-by-step explanation:
we know that
1 mile= 1.61 kilometers
To convert 1 kilometer to miles
use proportion
so
1/1.61 mi/km=x/1 mi/km
x=1 mi/1.61 km
To write this equation, you need use the formula y=mx+b.
m represents the slope and b represents the y intercept.
The y intercept is the point where the line touches the y axis. In this case, the y-intercept is 1.
The slope is just rise over run from one coordinate to another. The slope is 2/-1 which could be simplified as -2. The slope just means that we are going up 2 and left 1 to get to a new coordinate.
The equation is y=-2x+1
Have a good day! :)
9514 1404 393
Answer:
a. $3,455.20
Step-by-step explanation:
The monthly payment is given by the amortization formula:
A = P(r/12)/(1 -(1 +r/12)^(-12t))
for loan amount P at annual rate r for t years.
For this mortgage, we use P = $530,000, r = 0.068, t = 30.
A = $530,000(0.068/12)/(1 -(1 +0.068/12)^(-360)) ≈ $3,455.20
The monthly payment is $3,455.20.
_____
<em>Additional comment</em>
In 7 years, the balloon payment will be $481,559.91.
Answer:
see below
Step-by-step explanation:
(ab)^n=a^n * b^n
We need to show that it is true for n=1
assuming that it is true for n = k;
(ab)^n=a^n * b^n
( ab) ^1 = a^1 * b^1
ab = a * b
ab = ab
Then we need to show that it is true for n = ( k+1)
or (ab)^(k+1)=a^( k+1) * b^( k+1)
Starting with
(ab)^k=a^k * b^k given
Multiply each side by ab
ab * (ab)^k= ab *a^k * b^k
( ab) ^ ( k+1) = a^ ( k+1) b^ (k+1)
Therefore, the rule is true for every natural number n
