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Free_Kalibri [48]
3 years ago
11

Solution for 3/4x - 12 = -18?

Mathematics
2 answers:
Ivanshal [37]3 years ago
8 0

Answer:

x = -8

Step-by-step explanation:

Add 12 on both sides

You get 3/4x = -6

Multiply 4/3 on both sides

You get x = -24/3

Simplify and you get -8.

sergejj [24]3 years ago
8 0

Answer:

x=-8

Step-by-step explanation:

The reason why x is -8 is because

The first step is to isolate the x

To isolate the x you got to add 12 to both sides

\frac{3}{4}x-12+12=-18+12

the -12 gets canceled out by the positive twelve so all thats left now is

\frac{3}{4}x=-18+12,-18+12 is -6 so its  \frac{3}{4}x=-6

The second step is to divide

now you have to divide by \frac{3}{4} on both sides

\frac{\frac{3}{4} x}{\frac{3}4} } =\frac{-6}{\frac{3}{4} }

which \frac{3}{4} is taken out on the left side because its divided by itself so all thats left is a one,while on the right side -6 divided by three-fourths is -8

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Part A

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Part B

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Let 6-1/4•16+21 divided by 3 be Y

⇒ Y = (6-1/4•16+21) ÷ 3

⇒ Y = (6-0.25•16+21) ÷ 3 (Solving the bracket first and starting with the division operation)

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⇒ Y = (6-17) ÷ 3 (Conducting the addition operation next)

⇒ Y = (11) ÷ 3 (Conducting the subtraction operation next)

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Hence, Y = 3.333...

Part C

(8-5) (5-3) to the second power indicates that the brackets need to be solved first. Also, power operation is conducted before division or multiplication.

Let (8-5) (5-3) to the second power be Z

⇒ Z =  (3) (2) to the second power (Solving the brackets first)

⇒ Z =  (3) (2²) (Conducting the power operation next)

⇒ Z =  (3) (4)

⇒ Z =  12 (Conducting the multiplication operation next)

Hence, Z = 12.

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Step-by-step explanation:

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Initially a tank contains 10 liters of pure water. Brine of unknown (but constant) concentration of salt is flowing in at 1 lite
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Answer:

Therefore the concentration of salt in the incoming brine is 1.73 g/L.

Step-by-step explanation:

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Let the amount salt in the tank at any time t be Q(t).

\frac{dQ}{dt} =\textrm {incoming rate - outgoing rate}

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Therefore the concentration of salt in the incoming brine is 1.73 g/L

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