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Leni [432]
3 years ago
14

Can you help me with this question.

Mathematics
1 answer:
Sauron [17]3 years ago
6 0

Answer:

27. (2x + 3)(x + 5)

Step-by-step explanation:

27.

Use the 'ac' method

a*c = 2 * 15 = 30

We need 2 numbers whose product is 30 and whose sum is 13.

3 and 10 look good so we write

2x^2 + 10x + 3x + 15

= 2x(x + 5) + 3(x + 5)

= (2x + 3)(x + 5)  answer

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Write the phrase as an expression.<br><br> the product of 3+12<br><br> an expression is _____
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Writing expressions | Math (article) | Khan Academy

Step-by-step explanation:

8 0
3 years ago
An ipad is worth R1200, excluding 15% VAT. What is the selling price of the ipad including VAT
alukav5142 [94]

Answer:

R1,380

Step-by-step explanation:

The price of the iPad without VAT is R1200

We calculate 15% to get;

=  \frac{15}{100}  \times 1200

= 180

Now the selling price of the iPad including VAT

1200 + 180

= 1380

Therefore, the selling price of the ipad including VAT is R1380

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4 years ago
Find m&lt;1 and find m&lt;2
xenn [34]

Answer:

m∠1 = 50°

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Explanation:

m∠2 = 130° because of alternate exterior angles.

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8 0
3 years ago
A ball of radius 15 has a round hole of radius 5 drilled through its center. Find the volume of the resulting solid. Hint: The u
OverLord2011 [107]

Answer:

The volume of the ball with the drilled hole is:

\displaystyle\frac{8000\pi\sqrt{2}}{3}

Step-by-step explanation:

See attached a sketch of the region that is revolved about the y-axis to produce the upper half of the ball. Notice the function y is the equation of a circle centered at the origin with radius 15:

x^2+y^2=15^2\to y=\sqrt{225-x^2}

Then we set the integral for the volume by using shell method:

\displaystyle\int_5^{15}2\pi x\sqrt{225-x^2}dx

That can be solved by substitution:

u=225-x^2\to du=-2xdx

The limits of integration also change:

For x=5: u=225-5^2=200

For x=15: u=225-15^2=0

So the integral becomes:

\displaystyle -\int_{200}^{0}\pi \sqrt{u}du

If we flip the limits we also get rid of the minus in front, and writing the root as an exponent we get:

\displaystyle \int_{0}^{200}\pi u^{1/2}du

Then applying the basic rule we get:

\displaystyle\frac{2\pi}{3}u^{3/2}\Bigg|_0^{200}=\frac{2\pi(200\sqrt{200})}{3}=\frac{400\pi(10)\sqrt{2}}{3}=\frac{4000\pi\sqrt{2}}{3}

Since that is just half of the solid, we multiply by 2 to get the complete volume:

\displaystyle\frac{2\cdot4000\pi\sqrt{2}}{3}

=\displaystyle\frac{8000\pi\sqrt{2}}{3}

5 0
4 years ago
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