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yaroslaw [1]
3 years ago
14

Im Triggered Pls Dont DELETE!

Mathematics
2 answers:
Alex777 [14]3 years ago
8 0

2ex + 10x

The derivative is 2e + 10

stepladder [879]3 years ago
7 0

I'm assuming you mean f(x) = (e^x + 5x)^2, not f(x) = (e x + 5x)2, like your prompt suggests.


First, let's figure out what rule we can use. A likely noticeable one is the Power Rule, which says the following:

\dfrac{d}{dx} [u^a] = a(u)^{a-1} du


Applying this, we can solve for the derivative:

f'(x) = 2(e^x + 5x) (e^x + 5)

  • Apply the Power Rule

While you can simplify the expression to your liking, I believe that this form is not overly complex and will thus leave it as is.


Thus, our answer is:

f'(x) = \boxed{2 (e^x + 5x)(e^x + 5)}

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If f(3) = 9, what is f(1)<br>​
Vaselesa [24]

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3

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3*3=9

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The perimeter of a square is 80 cm. What is the area?
Vesna [10]

Answer:

A = 400 cm^2

Step-by-step explanation:

The perimeter of a square is given by

P = 4s where s is the side length

80 = 4s

Divide each side by 4

80/4 = 4s/4

20 =s

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4 0
3 years ago
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4 0
2 years ago
Evaluate : <br> \(\cos 12 \cos 24 \cos 36 \cos 48 \cos 72 \cos 84\)
NeTakaya
The answer in itself is 1/128 and here is the procedure to prove it:
cos(A)*cos(60+A)*cos(60-A) = cos(A)*(cos²60 - sin²A) 

<span>= cos(A)*{(1/4) - 1 + cos²A} = cos(A)*(cos²A - 3/4) </span>

<span>= (1/4){4cos^3(A) - 3cos(A)} = (1/4)*cos(3A) </span>

Now we group applying what we see above

<span>cos(12)*cos(48)*cos(72) = </span>
<span>=cos(12)*cos(60-12)*cos(60+12) = (1/4)cos(36) </span>

<span>Similarly, cos(24)*cos(36)*cos(84) = (1/4)cos(72) </span>

<span>Now the given expression is: </span>

<span>= (1/4)cos(36)*(1/4)*cos(72)*cos(60) = </span>

<span>= (1/16)*(1/2)*{(√5 + 1)/4}*{(√5 - 1)/4} [cos(60) = 1/2; </span>
<span>cos(36) = (√5 + 1)/4 and cos(72) = cos(90-18) = </span>
<span>= sin(18) = (√5 - 1)/4] </span>
<span>And we seimplify it and it goes: (1/512)*(5-1) = 1/128</span>
4 0
4 years ago
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