All categories

2 years ago

Im Triggered Pls Dont DELETE!

Mathematics

2 answers:

Alex777 [14]2 years ago

8 0

2ex + 10x

The derivative is 2e + 10

stepladder [879]2 years ago

7 0

I'm assuming you mean $f(x) = (e^x + 5x)^2$ , not $f(x) = (e x + 5x)2$ , like your prompt suggests.

First, let's figure out what rule we can use. A likely noticeable one is the Power Rule, which says the following:

$\dfrac{d}{dx} [u^a] = a(u)^{a-1} du$

Applying this, we can solve for the derivative:

$f'(x) = 2(e^x + 5x) (e^x + 5)$

Apply the Power Rule

While you can simplify the expression to your liking, I believe that this form is not overly complex and will thus leave it as is.

Thus, our answer is:

$f'(x) = \boxed{2 (e^x + 5x)(e^x + 5)}$

You might be interested in

Will mark brainlest please help!!!!<br> all the choices are the same

Bumek [7]

Going from top to bottom.

The first graph is labeled x≤−5.

The second graph is labeled x>5.

The third graph is labeled x≥−5.

The fourth graph is labeled x>5.

You can find All of these by graphing each inequality.

7 0

2 years ago

find h and k such that the equation 3x^2 -hx +4k =0, so that the sum of the solutions is -12 and the product of the solutions is

Radda [10]

Let the solutions be a and b.
a = -2; b = -10
a + b = -2 + (-10) = -12
ab = (-2)(-10) = 20

(x - a)(x - b) = 0

(x - (-2))(x - (-10)) = 0

(x + 2)(x + 10) = 0

x^2 + 10x + 2x + 20 = 0

x^2 + 12x + 20 = 0

-h = 12

h = -12

4k = 20

k = 5

6 0

3 years ago

Which expression represents the difference between 2n and 15

ValentinkaMS [17]

Is these the choices to chose from:
<span>A) 2n-15
B) 15-2n
C) Both A and B
D) Neither A nor B

*If so, i think its C*</span>

4 0

3 years ago

Convert 22 2/5% into decimal

Vera_Pavlovna [14]

Answer:

0.224

Step-by-step explanation:

2/5% = 0.004

22% = 0.22

22% + 2/5% = 0.224

5 0

3 years ago

Read 2 more answers

A bag contains 4 blue marbles and 2 yellow marbles. Two marbles are randomly chosen (the first marble is NOT replaced before dra

VMariaS [17]

Answer:

0.4 = 40% probability that both marbles are blue.

0.0667 = 6.67% probability that both marbles are yellow.

53.33% probability of one blue and then one yellow

If you are told that both selected marbles are the same color, 0.8571 = 85.71% probability that both are blue

Step-by-step explanation:

To solve this question, we need to understand conditional probability(for the final question) and the hypergeometric distribution(for the first three, because the balls are chosen without being replaced).

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

What is the probability that both marbles are blue?

4 + 2 = 6 total marbles, which means that $N = 6$

4 blue, which means that $k = 4$

Sample of 2, which means that $n = 2$

This is P(X = 2). So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 2) = h(2,6,2,4) = \frac{C_{4,2}*C_{2,0}}{C_{6,2}} = 0.4$

0.4 = 40% probability that both marbles are blue

What is the probability that both marbles are yellow?

4 + 2 = 6 total marbles, which means that $N = 6$

2 yellow, which means that $k = 2$

Sample of 2, which means that $n = 2$

This is P(X = 2). So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 2) = h(2,6,2,2) = \frac{C_{2,2}*C_{4,0}}{C_{6,2}} = 0.0667$

0.0667 = 6.67% probability that both marbles are yellow.

What is the probability of one blue and then one yellow?

Total is 100%.

Can be:

Both blue(40%)

Both yellow(6.67%)

One blue and one yellow(x%). So

40 + 6.67 + x = 100

x = 100 - 46.67

x = 53.33

53.33% probability of one blue and then one yellow.

If you are told that both selected marbles are the same color, what is the probability that both are blue?

Conditional probability.

Event A: Both same color

Event B: Both blue

Probability of both being same color:

Both blue(40%)

Both yellow(6.67%)

This means that $P(A) = 0.4 + 0.0667 = 0.4667$

Probability of both being the same color and blue:

40% probability that both are blue, which means that $P(A \cap B) = 0.4$

Desired probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.4}{0.4667} = 0.8571$

If you are told that both selected marbles are the same color, 0.8571 = 85.71% probability that both are blue

8 0

2 years ago