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sergey [27]
4 years ago
10

Given that 9554 divided by 562 equals 17 how can you find the quotient 95540 divided by 562

Mathematics
2 answers:
Nadusha1986 [10]4 years ago
7 0
It would be 170 because you just add a zero at the end since the number only changed by adding one zero. 
liq [111]4 years ago
4 0

Answer: Hello!

ok, here we know that 9554 divided by 562 is equal to 17; this is

9554/562 = 17

Now we have the number 95540 divided by 562, and we want to solve this using the prior information:

Is easy to see that 95540 = 10*9554, then:

95540/562 = (10*9554)/562

now we can use the commutative property of the multiplication and get:

(10*9554)/562  = 10*(9554/562) = 10*17 = 170

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Which of the following statements is false? (N = natural numbers) <br> Ø N <br> {0} N <br> {1} N
Iteru [2.4K]
Assuming each statement is claiming the first set is a subset of N, the second statement is false. 0 is not part of the natural numbers.
3 0
3 years ago
Read 2 more answers
What!!!?!?! Could someone help me with the first two I don't understand and it's due tomorrow
Delicious77 [7]
If said number is x, that means that twice (2 times) a number and 2x-7=13. Adding 7 to both sides, we get 2x=20 and by dividing both sides by 2 we get x=10. For 2, we see that the sum of a number and 6 is first priority, so we have (x+6)*7=-43. Dividing both sides by 7, we get x+6=-43/7. After that, we subtract both sides by 6 to get -43/7-6=x
3 0
3 years ago
Let $f(x) = x^2$ and $g(x) = \sqrt{x}$. Find the area bounded by $f(x)$ and $g(x).$
Anna [14]

Answer:

\large\boxed{1\dfrac{1}{3}\ u^2}

Step-by-step explanation:

Let's sketch graphs of functions f(x) and g(x) on one coordinate system (attachment).

Let's calculate the common points:

x^2=\sqrt{x}\qquad\text{square of both sides}\\\\(x^2)^2=\left(\sqrt{x}\right)^2\\\\x^4=x\qquad\text{subtract}\ x\ \text{from both sides}\\\\x^4-x=0\qquad\text{distribute}\\\\x(x^3-1)=0\iff x=0\ \vee\ x^3-1=0\\\\x^3-1=0\qquad\text{add 1 to both sides}\\\\x^3=1\to x=\sqrt[3]1\to x=1

The area to be calculated is the area in the interval [0, 1] bounded by the graph g(x) and the axis x minus the area bounded by the graph f(x) and the axis x.

We have integrals:

\int\limits_{0}^1(\sqrt{x})dx-\int\limits_{0}^1(x^2)dx=(*)\\\\\int(\sqrt{x})dx=\int\left(x^\frac{1}{2}\right)dx=\dfrac{2}{3}x^\frac{3}{2}=\dfrac{2x\sqrt{x}}{3}\\\\\int(x^2)dx=\dfrac{1}{3}x^3\\\\(*)=\left(\dfrac{2x\sqrt{x}}{2}\right]^1_0-\left(\dfrac{1}{3}x^3\right]^1_0=\dfrac{2(1)\sqrt{1}}{2}-\dfrac{2(0)\sqrt{0}}{2}-\left(\dfrac{1}{3}(1)^3-\dfrac{1}{3}(0)^3\right)\\\\=\dfrac{2(1)(1)}{2}-\dfrac{2(0)(0)}{2}-\dfrac{1}{3}(1)}+\dfrac{1}{3}(0)=2-0-\dfrac{1}{3}+0=1\dfrac{1}{3}

6 0
3 years ago
1 1/5 divided by 3/10
MissTica

Answer: <em><u>4.</u></em> This is because 1 and 1/5 = 1.2 and 3/10 = 0.3 and 1.2 divided by 0.3 = 4. That's because 1.2 can be split into 4 equal groups and each group has 0.3.

4 0
3 years ago
During the past half hour, a restaurant has had 23 orders for Pepsi and 15 orders for Mountain Dew. How many more orders have th
Bess [88]
Lets look at the info we have:-

23 orders for Pepsi.
15 orders for mountain dew.

Question:-
How many more orders have there been for Pepsi than for Mountain Dew?

To answer this we will subtract the amount of Pepsi's ordered by the amount of Mountain Dew's ordered. The answer will be the amount of more Pepsi's ordered than the Mountain Dew's.

23 - 15 = 8
8 more Pepsi's were sold than Mountain Dew's.

CHECK OUR WORK:-

15 + 8 = 23
We were RIGHT!!!

So, 8 more Pepsi's were ordered than Mountain Dew's.

Hope I helped ya!1 xD
5 0
3 years ago
Read 2 more answers
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