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2 years ago

Help please its math

Mathematics

1 answer:

gavmur [86]2 years ago

8 0

9514 1404 393

Answer:

partial products: 0.25, 1.5, 0.50, 3
Zoe spent $5.25 on apples

Step-by-step explanation:

The partial products are apparently derived by multiplying parts of each value on either side of the decimal point:

1.5 × 3.50 = (1 + 0.5)(3 + 0.50) = 1×3 + 0.5×3 +1×0.50 +0.5×0.50

= 3 + 1.5 + 0.50 + 0.25 . . . . . partial products

Their sum is ...

3 + 1.5 + 0.50 + 0.25 = 5.25

Zoe spent $5.25 on apples.

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Two times the first number added to the second number is -7

hodyreva [135]

2a+b=-7
5a+b=-13

b=-2a-7
5a-2a-7=-13
3a=-6
a=-2=first number

2(-2)+b=-7
-4+b+-7
b=-3=second

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3 years ago

Serggg [28]

Answer:

value of sides YZ is 36 cm

Step-by-step explanation:

Similar triangles states that the length of the corresponding sides are in proportion.

Given that: ΔABC is similar to ΔXYZ

then;

Corresponding sides are in proportion i.e

$\frac{AB}{XY}=\frac{BC}{YZ}=\frac{AC}{XZ}$ .....[1]

As per the statement:

side AB = 6 cm, side BC =18 cm and side XY = 12 cm.

Substitute these in [1] to solve for side YZ;

$\frac{6}{12}= \frac{18}{YZ}$

$\frac{1}{2} = \frac{18}{YZ}$

By cross multiply we have;

$YZ = 36$ cm

Therefore, the value of sides YZ is 36 cm

4 0

2 years ago

Read 2 more answers

A mirror with a reflecting surface that caves inward is said to be

Marysya12 [62]

C. CONCAVE

A mirror with a reflecting surface that caves inward is said to be CONCAVE.

Clue: caves inward. )(

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5 0

3 years ago

Looking at the top of tower A and base of tower B from points C and D, we find that ∠ACD = 60°, ∠ADC = 75° and ∠ADB = 30°. Let t

katrin2010 [14]

Answer:

$\text{Exact: }AB=25\sqrt{6},\\\text{Rounded: }AB\approx 61.24$

Step-by-step explanation:

We can use the Law of Sines to find segment AD, which happens to be a leg of $\triangle ACD$ and the hypotenuse of $\triangle ADB$ .

The Law of Sines states that the ratio of any angle of a triangle and its opposite side is maintained through the triangle:

$\frac{a}{\sin \alpha}=\frac{b}{\sin \beta}=\frac{c}{\sin \gamma}$

Since we're given the length of CD, we want to find the measure of the angle opposite to CD, which is $\angle CAD$ . The sum of the interior angles in a triangle is equal to 180 degrees. Thus, we have:

$\angle CAD+\angle ACD+\angle CDA=180^{\circ},\\\angle CAD+60^{\circ}+75^{\circ}=180^{\circ},\\\angle CAD=180^{\circ}-75^{\circ}-60^{\circ},\\\angle CAD=45^{\circ}$

Now use this value in the Law of Sines to find AD:

$\frac{AD}{\sin 60^{\circ}}=\frac{100}{\sin 45^{\circ}},\\\\AD=\sin 60^{\circ}\cdot \frac{100}{\sin 45^{\circ}}$

Recall that $\sin 45^{\circ}=\frac{\sqrt{2}}{2}$ and $\sin 60^{\circ}=\frac{\sqrt{3}}{2}$ :

$AD=\frac{\frac{\sqrt{3}}{2}\cdot 100}{\frac{\sqrt{2}}{2}},\\\\AD=\frac{50\sqrt{3}}{\frac{\sqrt{2}}{2}},\\\\AD=50\sqrt{3}\cdot \frac{2}{\sqrt{2}},\\\\AD=\frac{100\sqrt{3}}{\sqrt{2}}\cdot\frac{ \sqrt{2}}{\sqrt{2}}=\frac{100\sqrt{6}}{2}={50\sqrt{6}}$

Now that we have the length of AD, we can find the length of AB. The right triangle $\triangle ADB$ is a 30-60-90 triangle. In all 30-60-90 triangles, the side lengths are in the ratio $x:x\sqrt{3}:2x$ , where $x$ is the side opposite to the 30 degree angle and $2x$ is the length of the hypotenuse.

Since AD is the hypotenuse, it must represent $2x$ in this ratio and since AB is the side opposite to the 30 degree angle, it must represent $x$ in this ratio (Derive from basic trig for a right triangle and $\sin 30^{\circ}=\frac{1}{2}$ ).