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ohaa [14]
3 years ago
9

Are perfect squares closed under subtraction

Mathematics
1 answer:
Iteru [2.4K]3 years ago
3 0

Answer:

  no

Step-by-step explanation:

The set of perfect squares includes {0, 1, 4, 9, 16, 25, ...}.

Subtracting a couple of the elements, we get ...

  4 - 1 = 3 . . . . not a member of the set

The set is NOT CLOSED under subtraction.

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Please help ASAP!!!!
DerKrebs [107]
Anwser:

y = 2x

Examples:

1.1= 1
2.2= 4
3.3= 9
4.4= 16
5.5= 25
6 0
3 years ago
A grocery store has small bags of apples for $5 and large bags of apples for $8. If you buy 6 bags and spend $45, how many of ea
ladessa [460]
Based on the given problem above, here is the given solution.
Given that small bags = $5
                 large bags = $8
                 6 bags = $45
                 ? = number of each size bag you bought
The answer based on the given values above is 5 LARGE BAGS and 1 SMALL BAG.
Since per large bag is $8. $8 x 5 = $40
And per small bag is $5 x 1 = $5
So this gives you a total of $45
hope this helps!
3 0
4 years ago
A sequence can be generated by using an=3an−1, where a1=7 and n is a whole number greater than 1.
mixer [17]

Answer:

7,10,13

Step-by-step explanation:

5 0
3 years ago
What is x^2 times 4x
Flura [38]
Say x is 1 1^2=1  4x=4 4*1=4  I believe that is what you were asking

6 0
4 years ago
Choose the domain for which each function is defined
klemol [59]

Answer:

Part 1) f(x)=\frac{x+4}{x} -----> x\neq 0

Part 2) f(x)=\frac{x}{x+4} ----> x\neq -4

Part 3)  f(x)=x(x+4) ----> All real numbers

Part 4) f(x)=\frac{4}{x^2+8x+16} ----> x\neq -4

Step-by-step explanation:

we know that

The domain of a function is the set of all possible values of x

Part 1) we have

f(x)=\frac{x+4}{x}

we know that

In a quotient the denominator cannot be equal to zero

so

For the value of x=0 the function is not defined

therefore

The domain is

x\neq 0

Part 2) we have

f(x)=\frac{x}{x+4}

we know that

In a quotient the denominator cannot be equal to zero

so

For the value of x=-4 the function is not defined

therefore

The domain is

x\neq -4

Part 3) we have

f(x)=x(x+4)

Applying the distributive property

f*(x)=x^2+4x

This is a vertical parabola open upward

The function is defined by all the values of x

therefore

The domain is all real numbers

Part 4) we have

f(x)=\frac{4}{x^2+8x+16}

we know that

In a quotient the denominator cannot be equal to zero

so

Equate the denominator to zero

x^2+8x+16=0

Remember that

x^2+8x+16=(x+4)^2

(x+4)^2=0

The solution is x=-4

so

For the value of x=-4 the function is not defined

therefore

The domain is

x\neq -4

6 0
3 years ago
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