Answer:
5
Step-by-step explanation:
2^2= 4
-4*2=-8
-8+3=5
Answer:
The horizontal distance between the parking lot and the launch site is 470 meters
Step-by-step explanation:
Let
x-----> the horizontal distance between the parking lot and the launch site
we know that
The tangent of angle of 12 degrees is equal to divide the altitude of 100 meters by the horizontal distance
so
tan(12°)=100/x
Solve for x
x=100/tan(12°)=470 meters
Answer: ∠ABE=20°
Step-by-step explanation:
∵ AB=BC
∴ ΔABC is a isosceles triangle
∵ ∠A=30
∴ ∠C=30
∵ The interior angle sum of triangle is 180°
∵ ∠A+∠B+∠C=180
30+∠B+30=180
∠B+60=180
∠B=120 (∠ABC)
∵ ∠EBD+∠ABE+∠ABC=linear pair
∴∠EBD+∠ABE+∠ABC=180°
4x+2x+120=180
6x+120=180
6x=60
x=10
∠ABE=2x=2(10)=20°
Hope this helps!! :)
Please let me know if you have any question
Company A would because it is the least with the lowest slope since it is not increasing very fast
