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dimulka [17.4K]
3 years ago
5

Creatinine, �!�!�!�, is a by-product of muscle metabolism, and creatinine levels in the body are known to be a fairly reliable i

ndicator of kidney function. The normal level of creatinine in the blood for adults is approximately 1.0mg per deciliter (dL) of blood. If the density of blood is 1.025g/mL, calculate the molality of a normal creatinine level in a 10.0mL blood sample. What is the osmotic pressure (in atm) of this solution at 25.0°C?
Chemistry
1 answer:
Inessa05 [86]3 years ago
7 0

Answer:

Explanation:

molecular weight of creatinine = 131

1 mg of creatinine = 1 x 10⁻³ / 131 = 7.63 x 10⁻⁶ mole of creatinine.

volume of solution = .1 L

mass of blood solution = .1 x 1025

= 102.5 g

mass of solvent = 102.5 g approximately

= .1025 kg

molality = mole of solute / mass of solvent in kg

= 7.63 x 10⁻⁶ / .1025 kg

= 74.44 x 10⁻⁶ .

Osmotic pressure :---

π V / T = nR     π is  osmotic pressure , V is volume of solution in liter , T is absolute temperature , n is molality .

π x .1 / 298 =  74.44 x 10⁻⁶ x .082

π = 18.19 x 10⁻³ atm

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