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3 years ago

Simplify and solve for x. 5(x+20)= 7x+30

Mathematics

2 answers:

hodyreva [135]3 years ago

6 0

Answer:

x = 35

Step-by-step explanation:

Solve for x:

5 (x + 20) = 7 x + 30

Expand out terms of the left hand side:

5 x + 100 = 7 x + 30

Subtract 7 x from both sides:

(5 x - 7 x) + 100 = (7 x - 7 x) + 30

5 x - 7 x = -2 x:

-2 x + 100 = (7 x - 7 x) + 30

7 x - 7 x = 0:

100 - 2 x = 30

Subtract 100 from both sides:

(100 - 100) - 2 x = 30 - 100

100 - 100 = 0:

-2 x = 30 - 100

30 - 100 = -70:

-2 x = -70

Divide both sides of -2 x = -70 by -2:

(-2 x)/(-2) = (-70)/(-2)

(-2)/(-2) = 1:

x = (-70)/(-2)

The gcd of -70 and -2 is -2, so (-70)/(-2) = (-2×35)/(-2×1) = (-2)/(-2)×35 = 35:

Answer: x = 35

valkas [14]3 years ago

4 0

Answer:

x = 35

Step-by-step explanation:

5(x+20)= 7x+30

5x + 100 = 7x + 30

-30 -30

5x + 70 = 7x

-5x -5x

70 = 2x

/2 /2

35 = x

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Recall the scenario about Eric's weekly wages in the lesson practice section. Eric's boss have been very impressed with his work

Alona [7]

Answer:

$1)\quad f(x)=\bigg\{\begin{array}{ll}12x&0\leq x$

2) D: x = [0, 24]

3) R: y = [0, 384]

4) see graph

Step-by-step explanation:

Eric's regular wage is $12 per hour for all hours less than 9 hours.

The minimum number of hours Eric can work each day is 0.

f(x) = 12x for 0 ≤ x < 9

Eric's overtime wage is $18 per hour for 9 hours and greater.

The maximum number of hours Eric can work each day is 24 (because there are only 24 hours in a day).

f(x) = 18(x - 8) + 12(8)

= 18x - 144 + 96

= 18x - 48 for 9 ≤ x ≤ 24

The daily wage where x represents the number of hours worked can be displayed in function format as follows:

$f(x)=\bigg\{\begin{array}{ll}12x&0\leq x$

2) Domain represents the x-values (number of hours Eric can work).

The minimum hours he can work in one day is 0 and the maximum he can work in one day is 24.

D: 0 ≤ x ≤ 24 → D: x = [0, 24]

3) Range represents the y-values (wage Eric will earn).

Eric's wage depends on the number of hours he works. Use the Domain (given above) to find the wage.

The minimum hours he can work in one day is 0.

f(x) = 12x

f(0) = 12(0)

= 0

The maximum hours he can work in one day is 24 (although unlikely, it is theoretically possible).

f(x) = 18x - 48

f(24) = 18(24) - 48

= 432 - 48

= 384

D: 0 ≤ y ≤ 384 → D: x = [0, 384]

4) see graph.

Notice that there is an open dot at x = 9 for f(x) = 12x

and a closed dot at x = 9 for f(x) = 18x - 48

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2 years ago

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The graph of g(x) is a transformation of the graph of f(x)=3x. Enter the equation for g(x) in the box. G(x) =.

dalvyx [7]

Function transformation involves changing the form of a function

The function g(x) is $\mathbf{g(x) = 8(2)^x}$

The function is given as:

$\mathbf{f(x) = 3^x}$

g(x) is an exponential function that passes through points (-2,2) and (-1,4).

An exponential function is represented as:

$\mathbf{y = ab^x}$

At point (-2,2), we have:

$\mathbf{2 = ab^{-2}}$

At point (-1,4), we have:

$\mathbf{4 = ab^{-1}}$

Divide both equations

$\mathbf{\frac 42=\frac{ab^{-1}}{ab^{-2}}}$

Simplify

$\mathbf{2=\frac{b^{-1}}{b^{-2}}}$

Apply law of indices

$\mathbf{2=b^{-1+2}}$

$\mathbf{2=b}$

Rewrite as:

$\mathbf{b =2}$

Substitute 2 for b in $\mathbf{2 = ab^{-2}}$

$\mathbf{2 =a(2^{-2})}$

This gives

$\mathbf{2 =a(\frac 14)}$

Multiply both sides by 4

$\mathbf{a = 8}$

Substitute 8 for (a) and 2 for (b) in $\mathbf{y = ab^x}$

$\mathbf{y = 8(2)^x}$

Express as a function

$\mathbf{g(x) = 8(2)^x}$

Hence, the function g(x) is $\mathbf{g(x) = 8(2)^x}$

Read more about exponential functions at:

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8 0

2 years ago

Fiona invested $1000 at 7% compounded continuously. At the same time, Maria invested $1100 at 7% compounded daily. How long will

Natali [406]

9514 1404 393

Answer:

14,201 years

Step-by-step explanation:

The two compound interest formulas are ...

A = P·e^(rt) . . . . . continuous compounding at rate r for t years

A = P·(1 +r/365)^(365t) . . . . . daily compounding at rate r for t years

We went the amounts to be equal:

1000·e^(0.07t) = 1100·(1+0.07/365)^(365t)

Dividing by 1000(1 +0.07/365)^(365t), we have ...

((e^0.07)/(1+0.07/365)^365)^t = 1.1

The base of the exponential on the left is ...

( e^0.07)/(1+0.07/365)^365 ≈ 1.00000671149321522

Taking logs, we have ...

t×ln(1.00000671149321522) = ln(1.1)

t = ln(1.1)/ln(1.00000671149321522) ≈ 0.09531018/(6.7114704·10^-6)

t ≈ 14,201.09 . . . . . years

It will take about 14,201 years for the investments to be equal.

_____

Additional comment

The investment value at that time will be about $5.269·10^434. (That's a larger number than anything countable in the known universe, including energy quanta.)

These calculations are beyond the ability of many calculators, so might need to be carefully rewritten if the calculator only keeps 10 significant digits, or only manages exponents less than 100.

This shows that daily compounding is very close in effect to continuous compounding. It would take almost 150 years to make a difference of 0.1% in value.

4 0

3 years ago

Simplify and solve for x. ​ ​ 5(x+20)= 7x+30

Simplify and solve for x. 5(x+20)= 7x+30