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TEA [102]
3 years ago
5

??????????? Neeeeed help

Mathematics
1 answer:
murzikaleks [220]3 years ago
4 0

Answer:

it would be 3 tons and 80 ibs

hope that helps...if i am wrong, i am sorry :-)

Step-by-step explanation:

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In the figure below, XY II WZ and are cut by transversals XV and YW.
Jet001 [13]

Answer:

C. 52°

Step-by-step explanation:

Because YWZ and VWZ are complete each other to 90° we can say VWZ is 52°.

6 0
4 years ago
Use the fact that the graph passes through (0,36) to find the coefficient a in f(x) = a(x + 3)(x + 1)(x - 2)(x – 3) a=
Ivan

The given equation is

f(x) =  a(x + 3)(x + 1)(x - 2)(x-3)

It is given that , when x=0, f(x)=36

Substituting these values

36 =  a(0 + 3)(0 + 1)(0 - 2)(0-3)
\\
36 = a(3)(1)(-2)(-3)
\\
36 = 18a
\\
a =2

So the  missing value of a is 2 .

4 0
4 years ago
Read 2 more answers
PLEASE HELP ME ON THIS QUESTION FAST
IrinaVladis [17]
The answer is y = 8x + 9
8 0
3 years ago
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Find the 10th term of the following geometric sequence.<br> 2, 10, 50, 250, ...
defon

Answer:

3906250

Step-by-step explanation:

We can notice that the ratio is 5. 10/2 = 5

Each term gets multiplied by 5 to get the next term.

250 × 5 = 1250 (5th term)

1250 × 5 = 6250 (6th term)

6250 × 5 = 31250 (7th term)

31250 × 5 = 156250 (8th term)

156250 × 5 = 781250 (9th term)

781250 × 5 = 3906250 (10th term)

The 10th term of the geometric sequence is 3906250.

8 0
4 years ago
Pls pls help! 50pts!!!
Alchen [17]

Answer:

I figured all these out by graphing the function. See the attachment for a picture.

h(x) = (x-1)^2

It's <u>increasing over (1, ∞)</u> because the values are going up in that span.

It's <u>decreasing over (-∞, 1)</u> because the values are going down in that span.

Its range is all values of <u>y </u>\geq<u> 0</u> (we can see that only y-values above 0 are in the function).

g(x) = -(x+1)(x-1)

It's <u>increasing over (-∞, 0)</u> because the values are going up in that span.

It's <u>decreasing over (0, ∞)</u> because the values are going down in that span.

Its range is all values of <u>y </u>\leq<u> -1</u> (we can see that only y-values below 1 are in the function).

5 0
3 years ago
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