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amid [387]
3 years ago
8

Math help on this question!

Mathematics
1 answer:
NemiM [27]3 years ago
6 0

Answer:

none

Step-by-step explanation:

110 + 60 = 170

but 170 is obviously not 180 sooo none will be 60 degrees

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5. The perimeter of a polygon is__________ equal to 2w+21.
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The answer to this question is A
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3 years ago
PLEASE HELP IMMEDIATELY
grandymaker [24]

Answer:

a)   C(d) = 37.95 + 0.62d

b)  C(74) = 37.95 + 0.62(74)

83.8 dollars

c) 8181 miles

Step-by-step explanation:

The company charges a fee of 37.95 just for the rent and then 0.62 dollars per mile.

So if one person travels one mile they will pay:

37.95 + 0.62

Two miles: 37.95 + 0.62 (2)

Three miles: 37.95 + 0.62 (3)

d miles: 37.95 + 0.62(d)

Thus, the function C(d) that gives the total cost of renting the truck for one day if you drive d miles would be C(d) = 37.95 + 0.62d

Now, if we drive 74 miles, the function that gives us the cost would be:

C(74) = 37.95 + 0.62(74) = 37.95 + 45.88 = 83.83 = 83.8 dollars

Now, if we have 5110 dollars on our budget, we would have to substitute this in our function to know how many miles we can drive with that amount:

C(d)= 37.95+0.62d=5110\\37.95+0.62d=5110\\0.62d=5110-37.95\\0.62d=5072.05\\d=5072.05/ 0.62 \\d=8180.7

Thus, we could drive 8181 miles

3 0
3 years ago
Someone please help ASAP!!!
WITCHER [35]

Answer:

I'm here, what do you need help with?

Step-by-step explanation:

6 0
3 years ago
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Are ABC and CDA congruent? Justify your answer. brainly
Setler79 [48]
Yes
because they have the same volume

5 0
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Current government spending to fund public schools is about 6×1011 dollars per year. The average cost nationally for a student t
NeX [460]

60000000 students can attend public schools with the current funding

<em><u>Solution:</u></em>

Given that Current government spending to fund public schools is about 6 \times 10^{11} dollars per year

The average cost nationally for a student to attend a public school for a year is about $10,000

To find: number of students can attend public schools with the current funding

\text{ current funding } = 6 \times 10^{11} \text{ dollars}

\text{ average cost for 1 student } = 10000 \text{ dollars }

Therefore,

\text{ number of students } = \frac{\text{ current funding }}{\text{ average cost of 1 student}}

Substituting the values we get,

\text{ number of students } = \frac{6 \times 10^{11}}{10000}\\\\\rightarrow \frac{6 \times 10^{11}}{10000} = \frac{6 \times 10^{11}}{10^4}\\\\\rightarrow \frac{6 \times 10^{11}}{10^4} = 6 \times 10^{11-4} = 6 \times 10^7\\\\\rightarrow 6 \times 10^7 = 60000000

Thus 60000000 students can attend public schools with the current funding

6 0
3 years ago
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