all
150+67=217 woohoo it's 217 not 2000 sooo him and all boxes
I think its.......5/15=1/3
Question is Incomplete, Complete question is given below.
Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.
Answer:
∆ABC is right angled triangle with right angle at B.
Step-by-step explanation:
Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.
We need to prove that triangle is the right angled triangle.
Let the triangle be denoted by Δ ABC with side as;
AB = (a - 1) cm
BC = (2√ a) cm
CA = (a + 1) cm
Hence,
Now We know that
So;
Now;
Also;
Now We know that
[By Pythagoras theorem]
Hence,
Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.
This proves that ∆ABC is right angled triangle with right angle at B.
Steve = S , Tom = T
1) S+T = 7777
2) S= 1414 + 2T
put 2) in 1)
1414+2T + T = 7777
1414 +3T = 7777
3T = 6363
so T = 2121
then Steve sold 1414+2(2121) = 1414+4242=5656 tickets
while Tom sold 2121 tickets
The location AC + CB is mathematically given as
AC + CB= AB
This is further explained below.
<h3>What is the location AC + CB of AB ?</h3>
Because point C can be seen to be in between A and point B, the equation AC + CB must equal AB.
It is important to keep in mind that point C may be located in any part of the space between A and B; yet, the solution will still be considered to be AB in this scenario.
Again, AC + CB = AB.
In conclusion, By way of deduction: if point C is located between points A and B, then it follows that point C is situated on line AB conversely, if point C is not situated on line AB, then it cannot be located between points A and B. As a result, you are able to deduce that AB is a line and that point C is situated on it in the middle of points A and B.
Read more about location
brainly.com/question/11718756
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