Answer: B&E
The answer is b and c I hope dat help
Suppose J, K, L, M, N are points on the same line.
MK = MN + (-KN) = MN - KN = 9x - 11 - x - 3 = 8x - 14
Since LK = MK and LK = 7x - 10, then
7x - 10 = 8x - 14
8x - 7x = -10 + 14
x = 4
LJ = MK + KJ
MK = LK = 7x - 10 = 7(4) - 10 = 28 - 10 = 18
LJ = 18 + 28 = 46
So let f(x) = x^(2/3)
<span>Then let f'(x) = 2/3 x^(-1/3) = 2 / (3x^(1/3)) </span>
<span>When x = 8, </span>
<span>f(8) = 8^(2/3) = 4 </span>
<span>f'(8) = 2 / (3*8^(1/3)) = 1/3 </span>
<span>So near x = 8, the linear approximation is </span>
<span>f(x) ≈ f(8) + f'(8) (x - 8) </span>
<span>f(x) ≈ 4 + 1/3 (x - 8) </span>
<span>So the linear approximation for x = 8.03 is... </span>
<span>f(8.03) ≈ 4 + 1/3 (8.03 - 8) </span>
<span>f(8.03) ≈ 4 + 1/3 (0.03) </span>
<span>f(8.03) ≈ 4.01 </span>
<span>8.03^(2/3) ≈ 4.01 </span>
Answer:
There must be 35 red marbles.
Step-by-step explanation:
This question can be solved using a rule of three.
A probability is the number of desired outcomes divided by the number of total outcomes.
The probability of randomly choosing a red marble is 7/9.
This means that for each set of 9 marbles, 7 must be red.
There are 45 marbles in total in the bag and each is equally likely to be chosen. Work out how many red marbles there must be.
How many red marbles out of 45?
7 red - 9 marbles
x red - 45 marbles

Simplifying by 9


There must be 35 red marbles.
First, find the distance AB by the formula:

If A(0,-7) and B(8,8), then

Dilating polygon ABCD by a scale factor of 2 with the center of dilation at the origin to create polygon A′B′C′D′, you increase the distance AB twice, A'B'=2AB. Thus, A'B'=2·17=34 units.
Answer: AB=17 units, A'B'=34 units.