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Mice21 [21]
3 years ago
6

If you are 16 years old now, which equation could be used to solve for your age, F, 15 years from now?

Mathematics
1 answer:
jeka943 years ago
5 0

Answer:

16 + 15 = F

Step-by-step explanation:

  • 16 + 15 = F
  • F = 31

Answer for TTM

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Simplify completely 10x^6y^3+20x^3y^2
Sloan [31]
10x^6y^3+20x^3y^2 = 10x^3y^2(x^3y + 2)
3 0
4 years ago
The parallelogram shown below has an area of 60 units^2
Nuetrik [128]

Answer:

6 or 9 unit is the missing base

8 0
3 years ago
A company makes auto batteries. They claim that of their LL70 batteries are good for months or longer. Assume that this claim is
Katen [24]

Answer:

The probability that the sample proportion is within 0.03 of the population proportion is 0.468.

Step-by-step explanation:

The complete question is:

A company makes auto batteries. They claim that 84% of their LL70 batteries are good for 70 months or longer. Assume that this claim is true. Let p^ be the proportion in a random sample of 60 such batteries that are good for 70 months or more.  What is the probability that this sample proportion is within 0.03 of the population proportion? Round your answer to two decimal places.

Solution:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

\mu_{\hat p}=p\\

The standard deviation of this sampling distribution of sample proportion is:

\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

The information provided is:

p=0.84\\n=60

As the sample size is large, i.e. <em>n</em> = 60 > 30, the Central limit theorem can be used to approximate the sampling distribution of sample proportion of LL70 batteries that are good for 70 months or longer.

Compute the probability that the sample proportion is within 0.03 of the population proportion as follows:

P(-0.03

Thus, the probability that the sample proportion is within 0.03 of the population proportion is 0.468.

8 0
3 years ago
A sample of final exam scores is normally distributed with a mean equal to 23 and a variance equal to 16. Part (a) What percenta
deff fn [24]

Answer:

Let X = score of final exam.

X~normal(23, 16)

(a)

percentage of score between 19 and 27

= P(19 < X < 27)

= P((19-23) / sqrt(16) < Z < (27 - 23) / sqrt(16))

= P(-1 < Z < 1)

= 1 - P(Z <= -1) - P(Z >= 1)

= 1 - P(Z >= 1) - P(Z >= 1)

= 1 - 2*P(Z >= 1)

= 1 - 2(0.1587)

= 0.6826

= 68.26%

According to Normal Distribution Table

P(Z>=1) = 1 - P(Z<1) = 1-0.8413

So the final percentage is 68.26%

7 0
4 years ago
A bag contains 8 red balls and 4 white balls. Two balls are drawn without replacement. (Enter your probabilities as fractions.)
RoseWind [281]

Answer:

total marbles;12

after drawing red total counts are 7 red and 4 white       11 in total

probabilities are 4/11

6 0
3 years ago
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