Answer:
Let X = score of final exam.
X~normal(23, 16)
(a)
percentage of score between 19 and 27
= P(19 < X < 27)
= P((19-23) / sqrt(16) < Z < (27 - 23) / sqrt(16))
= P(-1 < Z < 1)
= 1 - P(Z <= -1) - P(Z >= 1)
= 1 - P(Z >= 1) - P(Z >= 1)
= 1 - 2*P(Z >= 1)
= 1 - 2(0.1587)
= 0.6826
= 68.26%
According to Normal Distribution Table
P(Z>=1) = 1 - P(Z<1) = 1-0.8413
So the final percentage is 68.26%
D.
Step-by-step explanation:
The line goes through those points
4, because 12/3 is 4 cause 3×4=12
132 : 89
There is no "another form"
Answer:1,15 2,14 3,13 4,12 5,11 6,10 7,9 8,8 {x,y}
There would be multiple answers for this question so what you have to do is find what doubles to 32 which would be 16 so you just have to find two numbers that add to 16 so the answers could be; 1,15 2,14 3,13 4,12 5,11 6,10 7,9 8,8
-2
-5 -4 -3 <u>-2</u> -1 0 1 2 3 4 5