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mylen [45]
3 years ago
14

A sample of final exam scores is normally distributed with a mean equal to 23 and a variance equal to 16. Part (a) What percenta

ge of scores are between 19 and 27? (Round your answer to two decimal places.)
Mathematics
1 answer:
deff fn [24]3 years ago
7 0

Answer:

Let X = score of final exam.

X~normal(23, 16)

(a)

percentage of score between 19 and 27

= P(19 < X < 27)

= P((19-23) / sqrt(16) < Z < (27 - 23) / sqrt(16))

= P(-1 < Z < 1)

= 1 - P(Z <= -1) - P(Z >= 1)

= 1 - P(Z >= 1) - P(Z >= 1)

= 1 - 2*P(Z >= 1)

= 1 - 2(0.1587)

= 0.6826

= 68.26%

According to Normal Distribution Table

P(Z>=1) = 1 - P(Z<1) = 1-0.8413

So the final percentage is 68.26%

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The equation in the slope-intercept form is:

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<h3>How to write the equation?</h3>

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To get the slope, we need two points on the line, by using the graph we can identify the points: (0, 3) and (2,4)

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6 0
2 years ago
Which description is correct for the polynomial 4x² + 3x +5?
antoniya [11.8K]

Answer:

A. Quadratic trinomial

Step-by-step explanation:

You can easily eliminate B and C because trinomial means there are three terms. B has monomial (one term) and C has binomial (two terms).

Now you have A and D. D is cubic which means the first term (4x²) would have to be cubed (4x³). Quadratic means it is squared.

5 0
3 years ago
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Sloan [31]

Answer:

Step-by-step explanation:

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4 0
3 years ago
Santos walks 2 kilometers south and then a certain number of kilometers east. He ends 5 kilometers away from his starting positi
IgorLugansk [536]

Answer:

\sqrt{21}\ km or  4.58\ km  

Step-by-step explanation:

we know that

Applying Pythagoras' Theorem, calculate how many kilometers eastward Santos walked

so

Let

x----> quantity of kilometers eastward that Santos walked

x^{2}=5^{2}-2^{2}

x^{2}=21

x=\sqrt{21}\ km ----> exact value

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6 0
3 years ago
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In a college of exactly 2920 students, exactly 55 % are male. What is the number of female students?
Annette [7]

Answer:

1305 female students

Step-by-step explanation:

Total no. of students = 2900

Percentage of students male = 55%

No. of students male = 55% of 2900

                                 = 55/100*2900

                                 = 1595

No. of female students = 2900 - 1595 = 1305

8 0
2 years ago
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