John played a note on his tuba that vibrated the air 70 times per second. If he played the note for 5 seconds, how many times di
2 answers:
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Answer:
(a) 720 ways
(b) 120 ways
(c) 24 ways
Step-by-step explanation:
Given
--- number of letters
Solving (a): Number of arrangements.
We have:
So, the number of arrangements is calculated as:
This gives:
This gives:
Solving (b): DA as a unit
DA as a unit implies that, we have:
[DA] N C E R
So, we have:
So, the number of arrangements is calculated as:
This gives:
This gives:
Solving (c): NCE as a unit
NCE as a unit implies that, we have:
D A [NCE] R
So, we have:
So, the number of arrangements is calculated as:
This gives:
This gives:
Answer:
a) number 2 and 3 appeared a minimum number of times
b) number 5 appeared a maximum number of times
c) number 1, 4 and 6 appear an equal number of times (4 times). Also number 2 and 3 appear an equal number of times (1 time)
d) Even numbers turned up 9 times. The even numbers in a dice are 2 4 and 6. Add up how many times they came up: 1+4+4=9
f) Odd numbers turned up 11 times. The odd numbers in a dice are 1, 3 and 5. Add up how many times they came up: 4+1+6=11
