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11Alexandr11 [23.1K]
3 years ago
15

Dante has 60 baseball cards. this is at least six more than three time as many cards as Anna. write and solve an inequality to r

epresent the situation.
Mathematics
2 answers:
Grace [21]3 years ago
4 0
A = # of cards Anna has
60 >= 3A + 6
54 >= 3A
A <= 18

Anon25 [30]3 years ago
3 0
D=dante's cards number
a=anna's cards number

d=60
this (d) is at least (smallest is, aka greater than or equal to or <u>></u>) 6 more than (+6) 3 times  as many as anna (3 times a or 3a)

d<u>></u>6+3a
d=60
60<u>></u>6+3a
subtract 6 from both sides
54<u>></u>3a
divide both sides by 3
18<u>></u>a
anna has at least 18 cards
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Answer:

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Step-by-step explanation:

Given:

- Daily high temperatures in St. Louis for the last week were as​ follows:

                                   95​, 92​, 93​, 92​, 95​, 90​, 90

Find:

a) Forecast the high temperature today, using a 3-day moving average.

b) Forecast the high temperature today, using a 2-day moving average.

c) Calculate the mean absolute deviation based on a 2-day moving average, covering all days in which you can have a forecast and an actual temperature.

d) The mean squared error for the​ 2-day moving average​

Solution:

a)

- The set of 3 day moving average is as follows:

4.   (95 + 92 + 93) ÷ 3 = 93.33⁰C

5.  (92 + 93 + 92) ÷ 3 = 92.33⁰C

6.  (93 + 92 + 95) ÷ 3 = 93.33⁰C

7.  (92 + 95 + 90) ÷ 3 = 92.33⁰C

8.  (95 + 90 + 90) ÷ 3 = 91.667⁰C

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b)

- The set of 2 day moving average is as follows:

3.   (95 + 92) ÷ 2 = 93.5⁰C

4.  (95 + 93) ÷ 2 = 92.5⁰C

5.  (93 + 92) ÷ 2 = 92.5⁰C

6.  (92 + 95) ÷ 2 = 93.5⁰C

7.  (95 + 90) ÷ 2 = 92.5⁰C

8. (90 + 90) ÷ 2 = 90⁰C

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T = 90 degrees

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4.   92.5⁰C            0.5                  0.25

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6.   93.5⁰C            3.5                  12.25

7.   92.5⁰C            2.5                  6.25

8.   90⁰C

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                              MAD = 1.9

d)

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                              MSE = (0.25+0.25+6.25+12.25+6.25)  / 5

                              MSE = 5.05

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3 years ago
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