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Tamiku [17]
3 years ago
10

Yolanda is saving for a new cell phone. So far she has saved $90 from her babysitting jobs. She calculated that this is 45% of t

he total amount that she needs to buy the phone. What is the total cost of the phone?
Mathematics
1 answer:
BARSIC [14]3 years ago
8 0

Answer:

$200

Step-by-step explanation:

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Find the unit rate.
IceJOKER [234]

Answer:

<em>Unit rate is 54 words per minute</em>

Step-by-step explanation:

297 / 5.5

297 ÷ 5.5 = 54

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4 1/3 divided by 4/7 (answer using fraction)
sertanlavr [38]

Answer:

Step-by-step explanation:

Use KCF method

Keep the first fraction

Change division to multiplication

Flip the second fraction.

4\frac{1}{3} ÷ \dfrac{4}{7}

=\dfrac{13}{3}*\dfrac{7}{4}\\\\\\=\dfrac{91}{12}\\\\\\= 7\dfrac{7}{12}

8 0
3 years ago
an insurance company crashed 4 cars at 5 mph the cost for each 4 crashes was $417, $454, $415, $232. compute the range, sample v
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Step-by-step explanation:

i dont know

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3 years ago
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How do I convert measurement units but in fractions
Margaret [11]

 

Step-by-step explanation:Image result for How do I convert measurement units IN FRACTIONS

Method 2 Converting Values with Multiple Units

Write down your problem. ...

Find the conversion for one unit. ...

Multiply your number by the conversion fraction. ...

Cancel out your units. ...

Multiply with another conversion fraction the same way. ...

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4 0
3 years ago
In a particular course, it was determined that only 70% of the students attend class on Fridays. From past data it was noted tha
siniylev [52]

Answer: Probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

Step-by-step explanation:

Since we have given that

Probability that students attend class on Fridays = 70% = 0.7

Probability that who went to class on Fridays would pass the course = 95% = 0.95

Probability that who did not go to class on Fridays would passed the course = 10% = 0.10

Let A be the event students passed the course.

Let E be the event that students attend the class on Fridays.

Let F be the event that students who did not attend the class on Fridays.

Here, P(E) = 0.70 and P(F) = 1-0.70 = 0.30

P(A|E) = 0.95,  P(A|F) = 0.10

We need to find the probability that they did not attend on Fridays.

We would use "Bayes theorem":

P(F\mid A)=\dfrac{P(F).P(A\mid F)}{P(E).P(A\mid E)+P(F).P(A\mid F)}\\\\P(F\mid A)=\dfrac{0.30\times 0.10}{0.70\times 0.95+0.30\times 0.10}\\\\P(F\mid A)=\dfrac{0.03}{0.695}=0.043

Hence, probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

8 0
4 years ago
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