Answer:
![x1=\frac{-2-2\sqrt{29401} }{245} x2=\frac{-2+2\sqrt{29401} }{245}](https://tex.z-dn.net/?f=x1%3D%5Cfrac%7B-2-2%5Csqrt%7B29401%7D%20%7D%7B245%7D%20%20x2%3D%5Cfrac%7B-2%2B2%5Csqrt%7B29401%7D%20%7D%7B245%7D)
Step-by-step explanation:
Step One: Convert
49/16x^2-2=-0.05x+4
Step Two: Multiply Both Sides by 80
245x^2-160=-4x+320
Step Three: Move everything to the left
245x^2+4x-480=0
Final Step: Quadratic Formula
![x1=\frac{-2-2\sqrt{29401} }{245} x2=\frac{-2+2\sqrt{29401} }{245}](https://tex.z-dn.net/?f=x1%3D%5Cfrac%7B-2-2%5Csqrt%7B29401%7D%20%7D%7B245%7D%20%20x2%3D%5Cfrac%7B-2%2B2%5Csqrt%7B29401%7D%20%7D%7B245%7D)
Answer:
29.87
Step-by-step explanation:
Answer:
The slide
Step-by-step explanation:
the slide cause they counting by 5s so there are 35 kids on that slide.
Answer: 2.093
Step-by-step explanation:
As per give , we have
Sample size : n= 20
Degree of freedom : df= n-1=19
Significance level : ![\alpha: 1-0.95=0.05](https://tex.z-dn.net/?f=%5Calpha%3A%201-0.95%3D0.05)
Since , the sample size is small (n<30) so we use t-test.
For confidence interval , we find two-tailed test value.
Using students's t-critical value table,
Critical t-value : ![t_{\alpha/2, df}=t_{0.025,19}=2.093](https://tex.z-dn.net/?f=t_%7B%5Calpha%2F2%2C%20df%7D%3Dt_%7B0.025%2C19%7D%3D2.093)
Thus, the critical value for the 95% confidence interval = 2.093
The answer: - 2.3 ≥ b ; which does not correspond with any of the answer choices; but most closely corresponds with: "Answer choice: [B]: b > -2.3 ."
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Explanation:
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Assuming we have:
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2.7 is greater than <u><em>or</em></u> equal to "(b + 5)";
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We would write:
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→ 2.7 ≥ b + 5 ;
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→ Subtract "5" from EACH side:
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→ 2.7 − 5 ≥ b + 5 − 5
→ - 2.3 ≥ b ; which does not correspond with any of the answer choices; but most closely corresponds with: "Answer choice: [B]: b > -2.3 ."
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