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steposvetlana [31]
2 years ago
7

When patterning a shotgun, what is a sufficient percentage of pellets within a 30-inch circle?.

Mathematics
1 answer:
schepotkina [342]2 years ago
8 0
55% to 60%
The pattern of pellets within a 30-inch circle should be of a proper, even density to ensure a clean kill. The pattern should contain a sufficient percentage of the load, which should be at least 55% to 60%.
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Write an equation of a line going through (5,7) and (4 , -4)
Ostrovityanka [42]

Answer:

The equation of this line would be y = 11x - 48

Step-by-step explanation:

To get this equation, we first have to find the slope. We do that with the slope eqaution.

m(slope) = (y2 - y1)/(x2 - x1)

m = (-4 - 7)/(4 - 5)

m = -11/-1

m = 11

Now we can use this slope and either point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - 7 = 11(x - 5)

y - 7 = 11x - 55

y = 11x - 48

6 0
3 years ago
Can someone please help.
AnnZ [28]
With what????????????????????
5 0
3 years ago
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What is the sum of the complex numbers 2 + 4i,and 3 − 7i, where i=-1
Elodia [21]

Answer:

5 - 3i.

Step-by-step explanation:

2 + 4i + 3 - 7i       Bring like terms together:

= 2 + 3 + 4i - 71

= 5 - 3i.

5 0
2 years ago
Read 2 more answers
The list below shows the Highlight in inches of the player on a man college basketball team
boyakko [2]

We have the data set:

{79, 83, 82, 78, 79, 77, 80, 73, 82, 72}

This data set has 10 items.

To complete the data summary is helpful to sort the data:

{72, 73, 77, 78, 79, 79, 80, 82, 82, 83}

The minimum value is 72.

<em>The quartile divides the data set in 4 parts. </em>

<em>The first quartile is the value for which 25% of the data is below.</em>

<em>The second quartile is the value for which 50% of the data is below. The second quartile is equivalent to the median.</em>

<em>The third quartile is the value for which 75% of the data is below.</em>

In this data set, as its size is a even number, the quartile fall between two positions, so we will calculate the average of this numbers.

The first quartile will fall in the position 0.25*10=2.5. Then we can calculate the 1st quartile as the average between the 2nd and 3rd number of the data set.

This values are 73 (2nd position) and 77 (3rd position), so the average is:

Q_1=\frac{73+77}{2}=75

We can repeat this with the other quartiles:

\begin{gathered} Q_2=M=\frac{79+79}{2}=79 \\ Q_3=\frac{82+82}{2}=82 \end{gathered}

Then:

The first quartile is 75.

The median (second quartile) is 79.

The third quartile is 82.

The maximum value is 83.

7 0
1 year ago
On Monday, Florencia's hair was h centimeters long. She got a haircut on Tuesday, so her hair was only 75%, percent of the lengt
topjm [15]

Answer:

Step-by-step explanation:

Alright, lets get started.

Florencia's length of hair on Monday = h

Now on Tuesday after haircut, her length is 75 %  of the length it was on Monday.

So, length of hairs on Tuesday will be = h * \frac{75}{100}

So, length of hairs on Tuesday will be = h*0.75

Means , length of hairs on Tuesday will be = 0.75 h

So after haircut, Florencia's hair was 0.75 h.   :  Answer

Hope it will help :)




8 0
3 years ago
Read 2 more answers
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