P=156 cm
l=6+5w
P=2(l+w)
156=2(6+5w+w)
156=2(6+6w)
156=12+12w
12+12w=156
12w=156-12
12w=144
w=12cm
l=6+5•12
l=6+60
l=66cm
Let us calculate the median; the 6th observation is 20, so it is 20. We need the 6th observation so that out of the 11 observations we have 5 above the median and 5 below (or equal). We also have that then Q1 is the median of the lowest 5 observations, hence 19 (14,16,19,19,20, the 3rd observation is 19). Similarly, we get that the median for the upper half of the observations, Q3 namely, is 22 (21,21,22,22,23, the 3rd observation is 22). Thus, the interquartile range is 3=Q3-Q1. According to our calculations, all observations are wrong.
Answer:
(f+g)(x)= 2x²+2x-2
Step-by-step explanation:
-x²+6x-1+3x²-4x-1 can be found by combining like terms.
2x²+2x-2
The length of the smaller leg is 3.79
<h3>How to determine the length of the smaller leg?</h3>
Represent the smaller leg with x.
So, we have:
-- Pythagoras theorem
This gives
2x^2 = 144/5
Divide by 2
x^2 = 72/5
This gives
x^2 = 14.4
Take the square root
x = 3.79
Hence, the length of the smaller leg is 3.79
Read more about right triangles at
brainly.com/question/6322314
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Answer:
where's the picture?
Step-by-step explanation:
can I have the pic po
