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podryga [215]
3 years ago
14

13m +19 =14m m = what​

Mathematics
2 answers:
dexar [7]3 years ago
4 0

Answer: m = 19

Step-by-step explanation:

Stella [2.4K]3 years ago
4 0
The answer would be 19

13m + 19 = 14m

13m - 14m = -19

-m = -19

M= 19
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11. 6.2 m B 1.8m Calculate the value of x. NOT TO SCALE​
soldier1979 [14.2K]

Answer:

24.19

Step-by-step explanation:

\tan(x)  =  \frac{6.2}{13.8}  \\  x =   {  \tan}^{1}  \frac{6.2}{13.8}  \\ x = 24.19320899

or the value of x can be 24.20

3 0
2 years ago
−3x−6+(−1)<br> need answer pls
Nimfa-mama [501]

Step-by-step explanation:

−3x−6+(−1)

-3x-7

<h2>Hope it helps you</h2>
7 0
3 years ago
Read 2 more answers
PLEASE HELP AND PLEASE SHOW YOUR WORKING
professor190 [17]

Answer:

S = 13 - x

T = (18 + x) / 2

Step-by-step explanation:

S = 18

T= 18

Sue gives away x, so subtract it from 18. But Tony gets x, so add it to 18 in his expression.

S = 18 - x

T= 18 + x

Sue eats 5 so subtract 5 from her expression. Tony eats half, so divide his expression by 2.

S = 18 - x - 5

T = 18 + x / 2

Simplify 18-5.

S = 13 - x

T = (18 + x) / 2

6 0
3 years ago
Select the choice that has the correct area and perimeter for the figure .
laila [671]

Answer: B

Step-by-step explanation:

8 0
3 years ago
triangle ABC is Isosceles CA and CB are equal AB is parallels to the x- axis. Work out the coordinate of A. Given that BC=5cm wo
BabaBlast [244]

Answer:

The perimeter of the triangle ABC is 17 cm.

Step-by-step explanation:

Consider the Isosceles triangle ABC.

The sides CA and CB are equal with measures, 5 cm.

The base angles are assumed to be <em>x</em>° each. Hence, the angle ACB is 2<em>x</em>°.

The altitude CP divides the base AB into two equal halves and the angle ACB is also cut into halves.

Consider the right angled triangle ACP.

The sum of all the angles in a triangle is 180°.

Determine the value of <em>x</em> as follows:

<em>x</em>° + <em>x</em>° + 90° = 180°

2<em>x</em>° = 90°

<em>x</em>° = 45°

Compute the length of side AP as follows:

cos\ 45^{0}=\frac{AP}{CA}

      \frac{1}{\sqrt{2}}=\frac{AP}{5}

     AP =\frac{5}{\sqrt{2}}\\\\AP=3.5

Then the length of side AB is:

AB = AP + PB

     = 3.5 + 3.5

     = 7 cm

The perimeter of triangle ABC is:

Perimeter = AB + CA + CB

                = 7 + 5 + 5

                = 17

Thus, the perimeter of the triangle ABC is 17 cm.

8 0
3 years ago
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