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2 years ago

7

Can someone help me Domain and range I would mark the brainlist

1 answer:

Ivenika [448]2 years ago

6 0

Answer:

b

Step-by-step explanation:

i did it yesterday

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NeX [460]

Answer:

$\frac{15}{ \sqrt{31} - 4}} = \sqrt{31} + 4$

Step-by-step explanation:

$\frac{15}{\sqrt{31} - 4}\\\\=\frac{15}{\sqrt{31} - 4} \times \frac{\sqrt{31} + 4}{\sqrt{31}+ 4} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ [ \ rationalizing \ the \ denominator \ ]\\\\=\frac{15( \sqrt{31} + 4 )}{(\sqrt{31})^2 - (4)^2} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ [ \ (a-b)(a+b) = a^2 - b^2 \ ]\\\\=\frac{15 ( \sqrt{31} + 4)}{31 - 16}\\\\=\frac{15 (\sqrt{31} + 4)}{15}\\\\= \sqrt{31} + 4$

6 0

2 years ago

What would be the expression?

Gala2k [10]

6*6-(3*3)-(2*2) is the answer

7 0

2 years ago

What is The area of this trapezoid?

Dennis_Churaev [7]

Answer:

24

Step-by-step explanation:

area of regualr trapezoid = 1/2 ( sum of parallel sides )( height)

= ( 0.5)(8+4)(4 ) =24

3 0

2 years ago

HELP if correct I give the best rating.

Charra [1.4K]

What do you need help in?

6 0

3 years ago

Given that OA = 2x + 9y, OB = 4x + 8y and CD = 4x - 2y, explain the geometrical relationships between the straight lines AB and

Step2247 [10]

Answer:

The geometrical relationships between the straight lines AB and CD is that they have the same slope

Step-by-step explanation:

Given

$OA = 2x + 9y$

$OB = 4x + 8y$

$CD = 4x - 2y$

Required

The relationship between AB, CD

Since AB is a straight line and O is the origin, then:

$AB = (c - a)x + (d - b)y$

Where:

$OA = ax + by$ ====> $OA = 2x + 9y$

$OB = cx + dy$ ====> $OB = 4x + 8y$

This implies that:

$a =2$ $b = 9$ $c = 4$ $d = 8$

So:

$AB = (c - a)x + (d - b)y$

$AB = (4 - 2)x + (8 - 9)y$

$AB = 2x -y$

So, we have:

$AB = 2x -y$

$CD = 4x - 2y$

Calculate the slope (m) of $AB\ and\ CD$

$m = \frac{Coefficient\ of\ y}{Coefficient\ of\ y}$

For AB

$m_1 = \frac{-1}{2}$

$m_1 = -\frac{1}{2}$

For CD

$m_2 = \frac{-2}{4}$

$m_2 = \frac{-1}{2}$

$m_2 = -\frac{1}{2}$

By comparison:

$m_1 = m_2 = -\frac{1}{2}$

This implies that both lines have the same slope

8 0

3 years ago