The model boxcar below is a scale drawing. The scale is

Helppppppppppppppppppp

pashok25 [27]

The answer is 1
Merry Christmas

8 0

3 years ago

2/9 + 1/3 = please show work, I am too old and don't remember this

Kruka [31]

Answer:

The correct answer would be 5/9.

Step-by-step explanation:

Convert 1/3 into 3/9.

Add 2/9 and 3/9 to get 5/9.

4 0

3 years ago

Read 2 more answers

A line with a slope of 3 passes through the points (-8,f) and (-9,7). What is the value of f

larisa [96]

Answer:

Step-by-step explanation:

Slope can be calculated by:

$m = \frac{y_2-y_1}{x_2-x_1}$

We know M, y1, x2, and x1. We want to calculate for y2

$\frac{f-7}{-8-(-9)} = 3\\\frac{f-7}{1} = 3\\f-7 = 3\\f = 10\\$

3 0

3 years ago

Read 2 more answers

The perimeter of a rectangular field is 336 m. If the length of the field is 89 m, what is its width?

exis [7]

The length of the field will be calculated as:
P=2(L+W)
P=376
W=89
thus substituting the values in the equation we get;
376=2(L+89)
376/2=(L+89)
solving for L;
188=L+89
L=188-89
L=99 yards
therefore the length is 99 yards

Hope it helps!

7 0

3 years ago

Suppose that the neighboring cities of Tweed and Ledee are long-term rivals. Neal, who was born and raised in Tweed, is confiden

Makovka662 [10]

Complete Question

The option to the blank space are shown on the first uploaded image

Answer:

Neal's decision is to fail to reject the null hypothesis (p 0.066). There is no sufficient evidence to prove the claim that the average electricity consumption of all Ledee household is greater than , 854.28 kWh

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 854.11$

The sample size is $n = 65$

The sample mean is $\= x = 879.28 \ kWh$

The standard deviation is $\sigma = 133.29 \ kWh$

The level of significance is $\alpha = 0.05$

The null hypothesis is $H_o: \mu = 854.11$

The alternative hypothesis is $H_a : \mu > 854.11$

The t-statistics is $t = 1.522$

The p-value is $p-value = 0.066$

Now from the given data we can see that

$p-value < \alpha$

Generally when this is the case , we fail to reject the null hypothesis

So

Neal's decision is to fail to reject the null hypothesis (p 0.066). There is no sufficient evidence to prove the claim that the average electricity consumption of all Ledee household is greater than , 854.28 kWh

8 0

3 years ago