I need help QUICK! with this difficult question

Using a number cube and this hat with 5 different-colored marbles, which simulation would help you answer this question? During

Arlecino [84]

Answer:

see the attachment

Step-by-step explanation:

We assume that the question is interested in the probability that a randomly chosen class is a Friday class with a lab experiment (2/15). That is somewhat different from the probability that a lab experiment is conducted on a Friday (2/3).

Based on our assumption, we want to create a simulation that includes a 1/5 chance of the day being a Friday, along with a 2/3 chance that the class has a lab experiment on whatever day it is.

That simulation can consist of choosing 1 of 5 differently-colored marbles, and rolling a 6-sided die with 2/3 of the numbers being designated as representing a lab-experiment day. (The marble must be replaced and the marbles stirred for the next trial.) For our purpose, we can designate the yellow marble as "Friday", and numbers greater than 2 as "lab-experiment".

The simulation of 70 different choices of a random class is shown in the attachment.

_____

Comment on the question

IMO, the use of 70 trials is coincidentally the same number as the first 70 days of school. The calendar is deterministic, so there will be exactly 14 Fridays in that period. If, in 70 draws, you get 16 yellow marbles, you cannot say, "the probability of a Friday is 16/70." You need to be very careful to properly state the question you're trying to answer.

5 0

3 years ago

Jules has 1200 and is spending 40 per week. kelsey has 400 and is saving 50 a week. in how many weeks, will jules and kelsey hav

expeople1 [14]

After x weeks:
Jules will have: 1,200 + 40 x.
Kelsey will have: 400 + 50 x.
If we want to know in how many weeks will they have the same amount of money, we will make an equation:
400 + 50 x = 1,200 + 40 x
50 x - 40 x = 1,200 - 400
10 x = 800
x = 800 : 10
x = 80
Answer: In 80 weeks they will have the same amount of money.

4 0

3 years ago

Select the correct answer. Which equation represents a function?

inn [45]

Answer:

C

Step-by-step explanation:

'x=' create vertical lines which are not functions whereas

'y=' create horizontal lines which are functions

7 0

3 years ago

In Exercises 3–10, use the Chain Rule to calculate the partial derivatives. Express the answer in terms of the independent varia

sashaice [31]

I'll use subscript notation for brevity, i.e.

$\dfrac{\partial f}{\partial x}=f_x$

3.

$f(x,y,z)=xy+z^2\implies\begin{cases}f_x=y\\f_y=x\\f_z=2z\end{cases}$

$x(r,s)=s^2\implies\begin{cases}x_r=0\\x_s=2s\end{cases}$

$y(r,s)=2rs\implies\begin{cases}y_r=2s\\y_s=2r\end{cases}$

$z(r,s)=r^2\implies\begin{cases}z_r=2r\\z_s=0\end{cases}$

By the chain rule,

$f_r=f_xx_r+f_yy_r+f_zz_r=2xs+4zr=2s^3+4r^3$

$f_s=f_xx_s+f_yy_s+f_zz_s=2ys+2xr=6rs^2$

4.

$x(r,s,t)=r+s-2t\implies\begin{cases}x_r=1\\x_s=1\\x_t=-2\end{cases}$

$y(r,s,t)=3rt\implies\begin{cases}y_r=3t\\y_s=0\\y_t=3r\end{cases}$

$z(r,s,t)=s^2\implies\begin{cases}z_r=0\\z_s=2s\\z_t=0\end{cases}$

By the chain rule,

$f_r=f_xx_r+f_yy_r+f_zz_r=y+3xt=3rt+3r+3s-6t^2$

$f_s=f_xx_s+f_yy_s+f_zz_s=y+4zs=3rt+4s^3$

$f_t=f_xx_t+f_yy_t+f_zz_t=-2y+3xr=3r+3s-12rt$

8 0

3 years ago

6-y+5y-6y help please with work if you can if not the answer is ok

Goshia [24]

You need to group the like terms (the terms with the same or no variable) together so it is:

5y-6y-y +6

Then you combine the like term and it becomes
5y-7y +6
-2y+6
which can also be written as 6-2y

Hope this helps :)

5 0

3 years ago

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