Answer:
A. , , x-Intercepts: , y-Intercepts: none.
Step-by-step explanation:
Let be the general equation of the circle, we must transform the expression into standard form to determine its center, radius and intercepts. The procedure is shown below:
1) Given.
2) Commutative and associative properties.
3) Compatibility with addition.
4) Definition of addition/Commutative and associative properties.
5) Perfect square trinomial/Result.
The equation of the circle centered in (h, k) in standard form is defined as:
(Eq. 1)
Where:
, - Coordinate of the center of the circle, dimensionless.
- Radius of the circle, dimensionless.
By direct comparison we find that circle is centered in and has a radius of 2.
Finally, we obtain the intercepts of the given function:
x-Intercepts ()
Roots are found analitically by Quadratic Formula:
y-Intercepts ()
Roots are found analitically by Quadratic Formula:
In a nutshell, there are no y-Intercepts.
We include a graphic including circle, center and x-Intercepts.
Finally, we came to the conclusion that correct answer is A.