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Oksana_A [137]
4 years ago
7

Y=5-1/2x x=-2,0,2,4​

Mathematics
1 answer:
telo118 [61]4 years ago
6 0

Answer:

y=6,5,4,3 are value for y

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Bob has a standard deck of playing cards. If he randomly draws a J, K, 2, and 2, what is the probability that the next card he d
nlexa [21]

Answer:

The correct answer has already been given (twice). I'd like to present two solutions that expand on (and explain more completely) the reasoning of the ones already given.


One is using the hypergeometric distribution, which is meant exactly for the type of problem you describe (sampling without replacement):


P(X=k)=(Kk)(N−Kn−k)(Nn)


where N is the total number of cards in the deck, K is the total number of ace cards in the deck, k is the number of ace cards you intend to select, and n is the number of cards overall that you intend to select.


P(X=2)=(42)(480)(522)


P(X=2)=61326=1221


In essence, this would give you the number of possible combinations of drawing two of the four ace cards in the deck (6, already enumerated by Ravish) over the number of possible combinations of drawing any two cards out of the 52 in the deck (1326). This is the way Ravish chose to solve the problem.


Another way is using simple probabilities and combinations:


P(X=2)=(4C1∗152)∗(3C1∗151)


P(X=2)=452∗351=1221


The chance of picking an ace for the first time (same as the chance of picking any card for the first time) is 1/52, multiplied by the number of ways you can pick one of the four aces in the deck, 4C1. This probability is multiplied by the probability of picking a card for the second time (1/51) times the number of ways to get one of the three remaining aces (3C1). This is the way Larry chose to solve the this.

Step-by-step explanation:


6 0
4 years ago
Read 2 more answers
For each value of u, determine whether it is a solution to 6u-1< −19. u Is it a solution? Yes or No 5 −4 −3 8
Agata [3.3K]

Answer:

No it is not a solution to 6u-1<-19

7 0
2 years ago
Roll needs to make a sauce mixture of 2/5 sand and 2/5 of clay and one for Pete Mas to put his plants yes 75 pounds of sand how
Rus_ich [418]

Answer:

187.5 pounds

Step-by-step explanation:

Fraction of sand = 2/5

Fraction of clay = 2/5

Fraction of peat = 1/5

Pounds of sand = 75

The total pounds of soil required to make Correct mixture : let that be x

Hence,

Using the sand Fraction and pounds which we know :

2/5 of x = 75

2x / 5 = 75

Cross multiply :

2x = 75 * 5

2x = 375

x = 375 / 2

x = 187.5

Required pond of sand =187.5 pounds

8 0
3 years ago
The sum of 3 times a number and 6 is equal to 2 times the number
Mrrafil [7]

Answer:

3x + 6 = 2x

Solving for x gives x = -6.

Step-by-step explanation:

Let the number be x, then:

3x + 6 = 2x

3x - 2x = -6

x = -6.

7 0
3 years ago
Please can someone help me
Andrews [41]
If sara leaves her bin out and a gallon of water is 3 litres
let the water in the bin be x
x=3 litres
the answer is 3 liters
please mark as brainliest
8 0
3 years ago
Read 2 more answers
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