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Eduardwww [97]
3 years ago
7

If Karen uses her cell phone for more than 30 hours a month, which company should Karen choose? Why?

Mathematics
2 answers:
Debora [2.8K]3 years ago
4 0
Karen should use company J.
liq [111]3 years ago
4 0

Your questions asks which company is the best for Karen to choose.

Lets look at Company J first.

Company J charges a subscription fee of $30 per month plus $1 per hour of use.

Alright, Karen used 30 hours in one month, so we would have to add one dollar of an hour of use. So $1 + 30 would be $30. Now we add the other $30 because Company J charges a fee of $30 per month. $30 + $30 would be $60 in total for Company J.

Company K charges no monthly fee, but charges $2 for every hour of use.  

Now, if Karen uses more than 30 hours a month, then $2 × 30 hours of use, that would be $60.

What would be the best Company to choose?

Remember, Karen uses more than 30 hours a month, I just took 30 for an example. I would say Company J is the best Company to choose.

Why?

Because Karen uses MORE than 30 hours a month, suppose it's 40, then Company J would charge 30 dollars fee per month plus 1 dollar per hour of use, which would be 40 + 30. In total that's 70 dollars per month.

Company K would Charge 2 dollars per every hour of use, and no monthly fee. So 2 × 40 would be 80 dollars per month.

Hope this helped!~

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Answer:

The value is P( X = m ) = (\frac{2}{3} )^{m-1 } * \frac{1}{3}

Step-by-step explanation:

From question we are told that

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Generally the probability of drawing a green marble is  

     P(g) =  \frac{1}{3}

Generally the probability of drawing a marble that is not green is  

     P(g') =  1 - \frac{1}{3} = \frac{2}{3}

From the question we are told that there will be continuous drawing of marbles from the jar (in such a way that after each marble is drawn it is being replaced) until a green marble drawn

  Let m be the number of times marbles has been drawn when a green marble was gotten

it then means that for m - 1 times the marbles where drawn a green marble was not obtain.

Generally the probability drawing m times is mathematically is mathematically represented as

    P( X = m ) = (P(g'))^{m-1 } * P(g)

=>  P( X = m ) = (\frac{2}{3} )^{m-1 } * \frac{1}{3}

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Step-by-step explanation:

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