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Eduardwww [97]
3 years ago
7

If Karen uses her cell phone for more than 30 hours a month, which company should Karen choose? Why?

Mathematics
2 answers:
Debora [2.8K]3 years ago
4 0
Karen should use company J.
liq [111]3 years ago
4 0

Your questions asks which company is the best for Karen to choose.

Lets look at Company J first.

Company J charges a subscription fee of $30 per month plus $1 per hour of use.

Alright, Karen used 30 hours in one month, so we would have to add one dollar of an hour of use. So $1 + 30 would be $30. Now we add the other $30 because Company J charges a fee of $30 per month. $30 + $30 would be $60 in total for Company J.

Company K charges no monthly fee, but charges $2 for every hour of use.  

Now, if Karen uses more than 30 hours a month, then $2 × 30 hours of use, that would be $60.

What would be the best Company to choose?

Remember, Karen uses more than 30 hours a month, I just took 30 for an example. I would say Company J is the best Company to choose.

Why?

Because Karen uses MORE than 30 hours a month, suppose it's 40, then Company J would charge 30 dollars fee per month plus 1 dollar per hour of use, which would be 40 + 30. In total that's 70 dollars per month.

Company K would Charge 2 dollars per every hour of use, and no monthly fee. So 2 × 40 would be 80 dollars per month.

Hope this helped!~

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Help me with both of these answers please
kiruha [24]

Answer:

Step-by-step explanation:

Proportional.

y = 9x

The constant is 9

8 0
3 years ago
Please I need help on solving for x
Sedaia [141]

Answer:

34^o=1/2((3x-2)^0-(x+6)^o)

68^o=3x^o-2^o-x^o-6^o

68^o+8^o=2x^o-8+8^o

76^o=2x^o-->x=38^o

\huge\boxed{\boxed{\underline{\textsf{\textbf{x=38}}}}}

<h3><u>---------------------</u></h3><h3><u>hope it helps...</u></h3><h3><u>have a great day!!</u></h3>

5 0
3 years ago
Janet deposited $9,600 into an account that pays 4.4 interest, compounded daily. At the end of nine months, how much interest ha
neonofarm [45]

bearing in mind that 9 months is not even a year, but since there are 12 months in a year, then 9 months is really 9/12 years.


\bf ~~~~~~ \stackrel{\textit{daily}}{\textit{Continuously}} \textit{Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$9600\\ r=rate\to 4.4\%\to \frac{4.4}{100}\dotfill &0.044\\ t=years\to \frac{9}{12}\dotfill &\frac{3}{4} \end{cases} \\\\\\ A=9600e^{0.044\cdot \frac{3}{4}}\implies A=9600e^{0.033}\implies A\approx 9922.09 \\\\\\


\bf \stackrel{\textit{interest earned}}{9922.09-9600\implies 322.09}

5 0
3 years ago
4. A sports car accelerates from rest to a final velocity of 64 m/s at a rate of 12.3
Ivanshal [37]

Answer:

t = 5.2\ s

Step-by-step explanation:

Given

a= 12.3m/s^2 --- acceleration

v = 64m/s --- final velocity

u =0m/s --- initial velocity (it is 0, because the car starts from rest)

Required

Determine the time taken

This will be solved using Newton's first equation of motion:

v = u + at

Substitute values for v, u and a

64 = 0 + 12.3*t

64 = 12.3t

12.3t = 64

Make t the subject

t = \frac{64}{12.3}

t = 5.2\ s

<em>Hence, the time taken is approximately 5.2 seconds</em>

6 0
3 years ago
Heeeeeeeelpppppppppp​
Mekhanik [1.2K]

Answer:

14.83 feet

Step-by-step explanation:

c^{2} =a^{2} +b^{2}

a=\sqrt{16^{2}-6^{2}  }

a=14.83 feet

8 0
3 years ago
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