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Blizzard [7]
4 years ago
11

The human body burns glucose for energy according to this chemical reaction: The products of the reaction are carbon dioxide and

water . Interestingly, all of the carbon dioxide and much of the water exits the body through the lungs: on every breath, the average person exhales of air, which is typically enriched to and water vapor by volume. In short, when a person loses weight by dieting, the weight that is lost actually departs his body as a gas, every time he exhales. Each kilogram of body fat lost requires exhaling about of carbon dioxide. Calculate how many breaths it takes an average person to "exhale" of fat. Round your answer to the nearest thousand. You'll need to know that the density of is .
Chemistry
1 answer:
denis-greek [22]4 years ago
5 0

Answer:

The average persons requires 75000 breaths to exhale 1.0 Kg of fat

Explanation:

Note: The question is incomplete. The complete question is given below:

"The human body burns glucose (C6H1206) for energy according to this chemical reaction:

C6H1206 + 602----> 6CO2 + 6H20

The products of the reaction are carbon dioxide (CO2) and water (H20). Interestingly, all of the carbon dioxide and much of the water exits the body through the lungs: on every breath, the average person exhales 500 mL of air, which is typically enriched to 4% CO2 and 5% water vapor by volume. In short, when a person loses weight by dieting, the weight that is lost actually departs his body as a gas, every time he exhales. Each kilogram of body fat lost requires exhaling about 3.0 kg of carbon dioxide. Calculate how many breaths it takes an average person to "exhale" 1.00 kg of fat. Round your answer to the nearest thousand. You'll need to know that the density of CO2 is 2.0 kg/m³”.

Volume of air exhaled on average per breath = 500 mL

Volume of CO2 exhaled per breath = 4/100 × 500 = 20 mL

Since, 1000000 mL = 1 m³;

20 mL = 0.00002 m³

3.0 kg of CO2 is exhaled per Kg of fat.

Density of CO2 = 2.0 Kg/m³

Volume = mass/density

Volume of 3.0 Kg CO2 = 3.0/2.0 = 1.5 m³

Number of breaths that will have a volume of 1.5 m³ = 1.5/0.00002 = 75000 breaths.

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Answer:

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b) Grams of sodium fluoride, NaF, that contain this much fluoride:

3.84 g

Explanation:

Step 1. calculate the volume of the tank:

Volume of cylinder =

\pi  r^{2}h ,

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h = depth = 21.80m

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Because both ppm and g/m3 are same quantity .

g/m^{3} =\frac{mass\ of\ F-(g)}{Volume\ m^{3}}\times 10^{6}

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mass of F- required = 1.740 g

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mass of 1 mole of NaF = 42 g

(from periodic table calculate molar mass)

2Na+F_{2}\rightarrow 2NaF

Here 1 mole of F2 produce = 2 mole of NaF

So,

38 g  of F2 produce = 2 x 42 g of NaF

38 g of F2 produce = 84 g of NaF

1 g of F2 produce = 84/38 g of NaF

1.74 g F2 produce =

\frac {84}{38}\times 1.74

1.74 g F2 produce = 3.84 g of NaF

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3 0
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Answer:

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Explanation:

Hello.

In this case, we can see that the mass of carbon of the unknown compound comes from the yielded mass of carbon dioxide, thus, we compute the moles of carbon as follows:

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Moreover, the mass of hydrogen comes from the yielded water, therefore we can also compute the moles of water:

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Thus, the ratio of the molecular formula to the empirical formula is:

\frac{30}{15}=2

Therefore, the molecular formula is twice the empirical formula:

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Which is actually ethane.

Regards.

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