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3 years ago

Choose the abiotic factors that characterize the tundra biome.

2 answers:

3 0

The only answer that makes sense is A.

Warm wet forests is a rainforest, arctic foxes are biotic, not abiotic, and little rainfall extreme temperatures is a desert.

olganol [36]3 years ago

3 0

The answer is since abiotic factors are things that are nonliving and tundras are very flat and cold.

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Suppose the formation of iodine proceeds by the following mechanism:

NARA [144]

Answer:

Overall reaction

H2(g) + 2ICI(g) -----> I2(g) +2HCl(g)

Overall Rate = k1[H2] [ICl]

Explanation:

Overall reaction

H2(g) + 2ICI(g) -----> I2(g) +2HCl(g)

The overall reaction is the sum of the two two reactions shown in the question. After the two reactions are summed up properly, this overall reaction equation his obtained.

Since K1<<K2 it means that step 1 is slower than step 2. Recall that the rate if reaction depends on the slowest step of the reaction. Hence

Overall Rate = k1[H2] [ICl]

3 0

2 years ago

A hot cup of coffee (treat it like water) rests on a windowsill. If it cools off from 90 C

kakasveta [241]

Answer:

1721.8ml

Explanation:

90-30=60

103,310÷60=1721.83333333

1721.83333333= 1721.8

5 0

3 years ago

Read 2 more answers

What mass of water is produced when 425 g of octane is burned?

Vitek1552 [10]

659. 48 g of water is produced

3 0

2 years ago

Rewrite 76.00 to have 1 sig fig.

Luba_88 [7]

Answer:

76.00

sig fig:4

decmials:2

scientific notation:7.600 x 10 1

words: seventy-six

p.s that one is on the right top side of ten

Explanation:

4 0

3 years ago

For the reactions system 2H2(g) + S2(g) 2H2S(g), a 1.00 liter vessel is found to contain 0.50 moles of H2, 0.020 moles of S2, an

Mnenie [13.5K]

Answer: 1) $2H_2(g)+S_2(g)\rightleftharpoons 2H_2S(g)$

Equilibrium constant is defined as the ratio of the product of concentration of products to the product of concentration of reactants each term raised to their stochiometric coefficients.

$K_{eq}=\frac{[H_2S]^2}{H_2]^2\times [S_2]}$

where [] = concentration in Molarity= $\frac{moles}{\text {Volume in L}}$

Thus $[H_2S]=\frac{68.5}{1.0}=68.5M$

$[H_2]=\frac{0.50}{1.0}=0.50M$

$[S_2]=\frac{0.020}{1.0}=0.020M$

$K_{eq}=\frac{[68.5]^2}{0.50]^2\times [0.020]}=938450$

As the value of K is greater than 1, the reaction is product favored.

2) $N_2O_4(g)\rightleftharpoons 2NO_2(g)$

$K_{eq}=\frac{[NO_2]^2}{[N_2O_4]}$

$K_{eq}=\frac{[0.500]^2}{[0.0250]}=10$

3) $N_2+3H_2\rightleftharpoons 2NH_3$

$K_{eq}=\frac{[NH_3]^2}{[N_2]\times [H_2]^3}$

4) Reactions which do not continue to completion are called equilibrium reactions as the rate of forward reaction is equal to the rate of backward direction.

3 0

2 years ago

Read 2 more answers