Is this a algebra question? I just want to know?
Answer:
a = $13.5
Step-by-step explanation:
Let a = adult tickets
Let c = children tickets
Translating the word problem into an algebraic equation;
<u>For the Martinez family;</u>
2a + 3c = $60
<u>For the Wright family;</u>
3a + 5c = $95.5
Thus, the simultaneous equations are;
..........equation 1
.........equation 2
We would use substitution method to solve;
From equation 2, we make a the subject of formula;
3a = 95.5 - 5c
a = (95.5 - 5c)/3
<em>Substituting the value of "a" into equation 1, we have;</em>
2[(95.5-5c)/3] + 3c = 60
Multiplying all through by 3;
2(95.5 - 5c) + 9c = 180
191 - 10c + 9c = 180
191 - c = 180
c = 191-180
c = $11
To find the value of a;
2a +3c = 60
<em>Substituting the value of "c" into the equation, we have;</em>
a = $13.5
<em>Therefore, the cost of an adult movie ticket is $13.5. </em>
Answer:
The one on the bottom right
Step-by-step explanation:
Answer:
the correct answer is b (4,2)
Answer:
2 animals
Step-by-step explanation:
Number of animals=40
Fraction of fish=3/4
=>number of fish=3/4*40=30
Fraction of cats=1/5
=>number of cats=1/5*40=8
Animals which are not cats or fish are=total number of animals-(number of cats + number of fish)
Animals which are not cats or fish=40-(8+30)
40-38
2 animals