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Roman55 [17]
3 years ago
7

Can you help me? y= x + 7

Mathematics
1 answer:
I am Lyosha [343]3 years ago
6 0

Answer:

your slope is 1/1 and your y-intercept is 7. you have to plot this on a graph.

Step-by-step explanation:

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8 - 3x4 + 6/2<br><br> what’s the answer? help plz i really need help
Anastaziya [24]

Answer:

3 2/5

Step-by-step explanation:

8-3x4

ok well do 3x4 that is 12

so do 12 minus 8 which is 4. and 4 as a fraction is 2/5 so

do 6/2 plus 2/5

which is.....

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3 and 2/5

6 0
3 years ago
If x^2y-3x=y^3-3, then at the point (-1,2), (dy/dx)?
zavuch27 [327]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2866883

_______________


          dy
Find  ——  for an implicit function:
          dx


x²y – 3x = y³ – 3


First, differentiate implicitly both sides with respect to x. Keep in mind that y is not just a variable, but it is also a function of x, so you have to use the chain rule there:

\mathsf{\dfrac{d}{dx}(x^2 y-3x)=\dfrac{d}{dx}(y^3-3)}\\\\\\&#10;\mathsf{\dfrac{d}{dx}(x^2 y)-3\,\dfrac{d}{dx}(x)=\dfrac{d}{dx}(y^3)-\dfrac{d}{dx}(3)}


Applying the product rule for the first term at the left-hand side:

\mathsf{\left[\dfrac{d}{dx}(x^2)\cdot y+x^2\cdot \dfrac{d}{dx}(y)\right]-3\cdot 1=3y^2\cdot \dfrac{dy}{dx}-0}\\\\\\&#10;\mathsf{\left[2x\cdot y+x^2\cdot \dfrac{dy}{dx}\right]-3=3y^2\cdot \dfrac{dy}{dx}}


                        dy
Now, isolate  ——  in the equation above:
                        dx

\mathsf{2xy+x^2\cdot \dfrac{dy}{dx}-3=3y^2\cdot \dfrac{dy}{dx}}\\\\\\&#10;\mathsf{2xy+x^2\cdot \dfrac{dy}{dx}-3-3y^2\cdot \dfrac{dy}{dx}=0}\\\\\\&#10;\mathsf{x^2\cdot \dfrac{dy}{dx}-3y^2\cdot \dfrac{dy}{dx}=-\,2xy+3}\\\\\\&#10;\mathsf{(x^2-3y^2)\cdot \dfrac{dy}{dx}=-\,2xy+3}


\mathsf{\dfrac{dy}{dx}=\dfrac{-\,2xy+3}{x^2-3y^2}\qquad\quad for~~x^2-3y^2\ne 0}


Compute the derivative value at the point (– 1, 2):

x = – 1   and   y = 2


\mathsf{\left.\dfrac{dy}{dx}\right|_{(-1,\,2)}=\dfrac{-\,2\cdot (-1)\cdot 2+3}{(-1)^2-3\cdot 2^2}}\\\\\\&#10;\mathsf{\left.\dfrac{dy}{dx}\right|_{(-1,\,2)}=\dfrac{4+3}{1-12}}\\\\\\&#10;\mathsf{\left.\dfrac{dy}{dx}\right|_{(-1,\,2)}=\dfrac{7}{-11}}\\\\\\\\ \therefore~~\mathsf{\left.\dfrac{dy}{dx}\right|_{(-1,\,2)}=-\,\dfrac{7}{11}}\quad\longleftarrow\quad\textsf{this is the answer.}


I hope this helps. =)


Tags:  <em>implicit function derivative implicit differentiation chain product rule differential integral calculus</em>

6 0
3 years ago
2.3 + 12.3x = 14.6 whats x?
FinnZ [79.3K]

Answer:

x = 1

Step-by-step explanation:

12.3 + 2.3 = 14.6

If you multiplied 12.3 by 1 it would still be 12.3

3 0
3 years ago
Y=2 when x= 1/4<br> Find the variation k
bagirrra123 [75]

Answer:

ther is no k

Step-by-step explanation:

7 0
3 years ago
Find the Inverse for the linear function.<br> J(x)= 5x - 6<br> F1(x)=
kondaur [170]
F-1(x) = x\5 + 6/5
hope this helps
4 0
3 years ago
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