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If each of the branches has half the area of the aorta, its linear scale factor is the square root of 1/2, or (√2)/2.
The diameter of one of the branches is (da×√2)/2.
Answer:
4/5 or 53°
Step-by-step explanation:
soh
cah
toa
you want soh
sine=opposite/hyp
therefore sine of C is 4/5
to find the degrees you have to something a lil different.
sin^-1 (theta)= 4/5
sin^-1(4/5)=theta
53°=theta
They both have to be above the x axis, which makes B incorrect. B will be below the x axis. If you have a graphing calculator or know where there is one of the net, you can try it.
A and D are both wrong. The 1/2 does not become 2. What will happen is that 2 will make the graph wider.
There's only 1 answer left and that is
C <<<<<===== answer.
C reflects right across the y axis.
Covert to a common denominator to help:
A LCD is 24.
12/24, 20/24, and 15/24
So 12/24, 15/24, 20/24
Convert back into their original denominators:
1/2, 5/8, 5/6.
F.
