There are 5 solutions for this system.
x^2 + 4y^2 = 100 ____1
4y - x^2 = -20 ____2
Add both 1 & 2 together. x^2 gets cancelled
4y^2 + 4y = 80 (send 80 to the other side and divide by 4)
Then equation the becomes : y^2 + y -20 =0
Now factorise the equation: (y+5) (y-4) = 0
Solve for y : y = -5 and y = 4
Using the values of y to find the values of x. From equation 1:
x^2 = 100 - 4y^2 x = /100 - 4y^2 (/ means square root) Replace values of y
y = -5, x = /100 - 4(-5)^2 = /100 - 100 = 0
y = 4, x = /100 - 4(4)^2 = / 100 - 64 = /36 = -6 or 6
Thus we have 6 solutions y = -5, 4 and x = -6, 0, 6
Is there more option choices since the ones that are visible rent correct
Maybe upload an image of the choice rather than text since it’s unreadable
Answer:
A. Weather conditions
Step-by-step explanation:
Remember
(x^m)(x^n)=x^(m+n)
and
if a^m=a^n, where a=a then n=m
(x^4)(x^n)=x^5
(x^4)(x^n)=x^(4+n)
x^(4+n)=x^5
therefor
4+n=5
minus 4
n=1
Plz I need point and brainlist but I think it’s 20
